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melisa1 [442]
3 years ago
10

Triangle 1 has vertices at (A,B), (C,D), and (E,F). Triangle 2 has vertices at (−A,B), (−C,D), and (−E,F). What can you conclude

about triangle 2?
Mathematics
1 answer:
k0ka [10]3 years ago
8 0

Answer:

It is a reflection of triangle 1 in the y-axis.

Step-by-step explanation:

The y coordinates are unchanged but the x coordinates have change sign.

Triangle 2 is the reflection of triangle 1 in the y-axis.

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I am confused please can you help me
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How do i find the area between the two curves
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A=22/10

A=integral(a,b) [f(x)-g(x)]dx

Since the function is even (the function is mirrored over the y axis) we can evaluate the integral from 0 to 1 and then multiply our answer by 2 since we have the same area on each side of the y axis.

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2*[int.(0, 1)[x^2]dx+int(0, 1)[2x^4]dx]

Now factor out constants.

2*[int(0,1)[x^2]dx+2int(0,1)[x^4]dx]

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Now solve.

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3 years ago
G(x) = –16x + x2 in vertex form.
Citrus2011 [14]

Answer:

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Add and subtract the square of half the coefficient of x.

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Observe that the first three terms is a perfect square trinomial.

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