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Mumz [18]
2 years ago
10

What is the y value in the solution to this system of linear equations?

Mathematics
1 answer:
Travka [436]2 years ago
8 0

Answer:

The y-value is -20

Step-by-step explanation:

So let's solve this by Elimination method;

-2(4x + 5y = -12)

4(2x + 3y = -16)

Let's Distribute;

-8x - 10y = 24

8x + 12y = -64

So x cancels out because -8 + 8 = 0

-10y + 12y = 2y

24 - 64 = -40

2y = -40

Divide both sides by 2;

y = -20

Now lets plug in y to find the value of x;

4x + 5(-20) = -12

4x - 100 = -12

Add 100 to both sides;

4x = 88

Divide both sides by 4;

x = 22

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Gavin goes for a run at a constant pace of 9 minutes per mile. Ten minutes later, Lars goes for a run, along the same route, at
sweet [91]

Answer:  The answer is 35 minutes.


Step-by-step explanation:  Given that Gavin goes for a run at a constant pace of 9 minutes per mile and after 10 minutes, Lars started running along the same route, at a constant pace of 7 minutes per mile. We need to find the number of minutes Lars will take to reach Gavin.

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d_G=\dfrac{1}{9}=\dfrac{7}{63}~\textup{miles}.

Similarly,

In 7 minutes, distance run by Lars = 1 mile.

So, in 1 minute, distance travelled by Lars will be

d_L=\dfrac{1}{7}=\dfrac{9}{63}~\textup{miles}.

Now, since Lars started after 10 minutes, so distance run by Gavin in those 10 minutes will be

d_{G10}=\dfrac{10}{9}=\dfrac{70}{63}~\textup{miles}.

Now, difference between Lars and Gavin's rate of runnings is

\dfrac{9}{63}-\dfrac{7}{63}=\dfrac{2}{63}.

Therefore, the time taken by Lars to reach Gavin is given by

t=\dfrac{\frac{70}{63}}{\frac{2}{63}}=35.

Thus, the required time is 365 minutes.  


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3 years ago
How do we calculate 25% of 300
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