Answer:
4x-y+1=0
Step-by-step explanation:
here,given equation of a line id
4x-y-2=0.. eqn(i)
equation of any line parallel to line (i) is
4x-y+k=0...eqn(ii)
since, the line(ii) passes through (1,5)[replacing x=1 and y=5 in eqn(ii), we get]
4*1-5+k=0
or, 4-5+k=0
or,-1+k=0
•°•k=1
substituting the value of k=1 in eqn(ii),
4x-y+1=0 is the required equation of the line.
9 is in parentheses therefore it's elevated above 3 that means you have to do operations on it first.
3 + (-9) = -6
The sum is negative.
Answer:
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Step-by-step explfdsanation:
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Answer:
See below, there may be more than one answer
Step-by-step explanation:
4(3+1)+2 = 18
(4+2)(3)+1 = 19
(1)(2+3)(4) = 20
(1+2)(3+4) = 21
Is there any options or anything to go with this?