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asambeis [7]
2 years ago
8

Write an equation where the variable is divided by a number, and a solution is -4/5

Mathematics
1 answer:
MrMuchimi2 years ago
8 0

Answer:

x/-5

Step-by-step explanation:

Just divide by 5 and the denominator will be 5 meaning x would have to be 4.

Make sure your 5 is negative so the whole equation also ends up negative. x/-5=-4/5

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The figure shown below is composed of a semicircle and a non-overlapping equilateral triangle and contains a hole that is also c
Sloan [31]

Check the picture below.

since we know the radius of the larger semicircle is 8, thus its diameter is 16, which is the length of one side of the equilateral triangle.  We also know the smaller semicircle has a radius of 1/3, and thus a diameter of 2/3, namely the lenght of one side of the small equilateral triangle.

now, if we just can get the area of the larger figure and the area of the smaller one and subtract the smaller from the larger, we'll be in effect making a hole/gap in the larger and what's leftover is the shaded figure.

\bf \stackrel{\textit{area of a semi-circle}}{A=\cfrac{1}{2}\pi r^2\qquad r=radius}~\hspace{10em}\stackrel{\textit{area of an equilateral triangle}}{A=\cfrac{s^2\sqrt{3}}{4}\qquad s=\stackrel{side's}{length}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{\Large Areas}}{\left[ \stackrel{\textit{larger figure}}{\cfrac{1}{2}\pi 8^2~~+~~\cfrac{16^2\sqrt{3}}{4}} \right]\qquad -\qquad \left[ \cfrac{1}{2}\pi \left( \cfrac{1}{3} \right)^2 +\cfrac{\left( \frac{2}{3} \right)^2\sqrt{3}}{4}\right]}

\bf \left[ 32\pi +64\sqrt{3} \right]\qquad -\qquad \left[ \cfrac{\pi }{18}+\cfrac{\frac{4}{9}\sqrt{3}}{4} \right] \\\\\\ \left[ 32\pi +64\sqrt{3} \right]\qquad -\qquad \left[ \cfrac{\pi }{18}+\cfrac{\sqrt{3}}{9} \right]~~\approx~~ 211.38 - 0.37~~\approx~~ 211.01

3 0
4 years ago
Marcel had drama practice 8.75 hours from Monday to Friday if he practices the same amount each day how many hours does marcel s
AURORKA [14]
It would be 1.75 hours each day 
5 0
3 years ago
A road 4 inches long on a map is 80 miles long in real life. A river is 2 ½ inches long on the map and is 50 miles long in real
jonny [76]
Not Proportional. Sorry if it’s wrong
7 0
3 years ago
The graph shows a system consisting of a linear equation and a quadratic equation.
Lorico [155]

Answer:

  (3, 4) and (5, 12)

Step-by-step explanation:

The points where the two curves intersect are the solutions to the system of equations:

  (3, 4) and (5, 12)

3 0
4 years ago
Soft drink consumption in New Zealand. A survey commissioned by the Southern Cross Healthcare Group reported that 16% of New Zea
lidiya [134]
<h2>Answer with explanation:</h2>

Given : The proportion of New Zealanders consume five or more servings of soft drinks per week :\hat{p}= 0.16

a) The number of survey respondents reported that they consume five or more servings of soft drinks per week = 2006

b) Confidence interval for population proportion (p) :

\hat{p}\pm z^*\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

, where \hat{p} = Sample proportion.

n= Sample size.

z* = Critical value.

For n= 2006 , \hat{p}= 0.16 and critical value for 95% confidence interval : z* = 1.96

Then , the required confidence interval will be :

0.16\pm (1.96)\sqrt{\dfrac{ 0.16(1- 0.16)}{2006}}

0.16\pm (1.96)\sqrt{ 0.000066999002991}

0.16\pm (1.96)(0.00818529186963)

0.16\pm 0.0160431720645

(0.16-0.0160431720645,\ 0.16+0.0160431720645)

(0.143956827935,\ 0.176043172064)\approx(0.144,\ 0.176)

i.e. A 95% confidence interval for the proportion of New Zealanders who report that they consume five or more servings of soft drinks per week. = (0.144,\ 0.176)

c) (0.144,\ 0.176)=(0.144\times100\%,\ 0.176\times100\%)

=(14.4\%,\ 17.6\%)176\times100\%)[/tex]

d) The estimate might be biased because the survey is taken online that means offline New Zealanders are out of consideration.

6 0
3 years ago
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