Stacy hits the jackpot one day at the gumball machine. She puts in a quarter and gets 444 gumballs rather than 111. The radius o
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Answer:
a) 17.09 hours
b) The 95% confidence interval estimate of the population mean flying time for the Pilots is between 31.91 hours and 66.09 hours
Step-by-step explanation:
We have the standard deviation of the sample, so we use the t distribution to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 49 - 1 = 48
95% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 48 degrees of freedom(y-axis) and a confidence level of . So we have T = 2.0106
The margin of error is:
M = T*s = 2.0106*8.5 = 17.09
s is the standard deviation of the sample. 17.09 hours is the answer for a.
The lower end of the interval is the sample mean subtracted by M. So it is 49 - 17.09 = 31.91 hours
The upper end of the interval is the sample mean added to M. So it is 49 + 17.09 = 66.09 hours
The 95% confidence interval estimate of the population mean flying time for the Pilots is between 31.91 hours and 66.09 hours
Answer:
Step-by-step explanation:
A point (x, y) with integer coordinates is randomly selected such that
The possible pairs of (x,y) are:
(0,0),(0,1),(0,2),(0,3),(0,4)
(1,0),(1,1),(1,2),(1,3),(1,4)
(2,0),(2,1),(2,2),(2,3),(2,4)
(3,0),(3,1),(3,2),(3,3),(3,4)
(4,0),(4,1),(4,2),(4,3),(4,4)
(5,0),(5,1),(5,2),(5,3),(5,4)
(6,0),(6,1),(6,2),(6,3),(6,4)
(7,0),(7,1),(7,2),(7,3),(7,4)
(8,0),(8,1),(8,2),(8,3),(8,4)
The Total Possible Outcomes n(S)= 45
The pair (x, y) that satisfies the given condition (say event A: ) are:
n(A)=15
Therefore: