Alexis worked for 59 hours, Becca worked for 74 hours and Cindy worked for 152 hours.
Step-by-step explanation:
Given,
Total hours worked by three of them = 285 hours
Let,
x represent the hours of Alexis.
y represent the hours of Becca.
z represent the hours of Cindy.
According to given statement;
x+y+z=285 Eqn 1
Alexis worked 15 hours less than Becca.
x = y-15 Eqn 2
z = 2y+4 Eqn 3
Putting value of x and z from Eqn 2 and 3 in Eqn 1

Dividing both sides by 4

Putting y=74 in Eqn 2

Putting y=74 in Eqn 3

Alexis worked for 59 hours, Becca worked for 74 hours and Cindy worked for 152 hours.
Keywords: linear equation, division
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<span>The two dice rolls are independent, so the fact that you roll an even number on the 2nd dice has no bearing on the probability that the first die shows a 1, 2, 3, or 6. Answer: 4/6 = 2/3.
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Using S = ut + 1/2gt², from rest, u = 0
S = 1/2gt², g ≈ 9.8 m/s²
S = <span>1/2 *9.8*3²
</span>S = 0.5<span> *9.8*3*3
</span>
<span>S ≈ 44.1 m</span>
Answer:
The hole is at (5,7)
Step-by-step explanation:
x^2 − 3x − 10
-------------------
x−5
Factor the numerator
(x-5)(x+2)
-------------------
x−5
There is a hole at x=5 since it will cancel in the numerator and the denominator
f(x) = x+2 and letting x = 5
f(5) = 5+2
The hole is at (5,7)