Line WX and line YZ intersect at point V. If angle WVY = 4a + 58 and angle XVY = 2b - 18, find the values of a and b so that lin
e WX is perpendicular to line YZ.
First answer gets brainlyest
First answer gets brainlyest
1 answer:
we know that
If line WX is perpendicular to line YZ
then
see the attached figure to better understand the problem
m∠WVY=90°--------> 4a+58=90-----> 4a=90-58-----> a=32/4------> a=8°
m∠XVY=90°--------> 2b-18=90----> 2b=90+18------> b=118/2-------> b=59°
therefore
<u>the answer is</u>
a) The value of a is 8 degrees
b) The value of b is 59 degrees
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We need to find the enter and radius of a circle using the completing the square method.
The steps are as following :
Step 1 [original equation]: x^2 − 10x + y^2 + 12y = 20 .
Step 2 [group like terms]: (x^2 − 10x) + (y^2 + 12y) = 20
Step 3 [complete the quadratics]: (x^2 − 10x + 25) + (y^2 + 12y + 36) = 20 + (25 + 36).
Step 4 [simplify the equation]: (x^2 − 10x + 25) + (y^2 + 12y + 36) = 64.
Step 5 [factor each quadratic]: (x − 5)^2 + (y + 6)^2 = 8^2
Step 6 [identify the center and radius]: Center = (5, −6) Radius = 8.
<h3>Step 6 is incorrect.</h3><h3>The center should be (5,-6).</h3><h3> Replace − 5 with + 5 and replace + 6 with − 6.</h3>Answer:
Step-by-step explanation:
Assuming this is a linear equation in the form of , we can first solve for the slope using
, for these points, the slope would be
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plugging in (7,5), we get ×
+
and solving for b, we get b =
therefore, the equation of the line passing through (7,5) and (1,2) is .
hope this helps!