Solve the following system for all solutions: (x - 1)^2 + (y + 3)^2 = 13 x + y = -3
1 answer:
Answer:
( -4, -1 ) and ( -9, - 6) Step-by-step explanation:
<h3>Given</h3>
(x - 1)^2 + (y + 3)^2 = 13
x + y = -3 <h3>Solution</h3>
<u>From the second equation we get</u>
<u>Substituting x in the first equation</u>
(- y - 3 - 1)^2 + (y + 3)^2 = 13 (-y - 4)^2 + (y + 3)^2 = 13 (y+4)^2 + (y+3)^2 = 13 y^2 + 8y + 16 + y^2 + 6y + 9 = 13 2y^2 + 14y + 12 = 0 y^2 +7y +6 = 0 (y+1)(y+6) = 0 y = - 1 y = - 6 <u>Then</u>
<u>Answer</u>
( -4, -1 ) and ( -9, - 6)
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