Answer:
x = 6/11
Step-by-step explanation:
2(-3x + 4 ) = 5x + 2
-6x + 8 = 5x + 2
- 2 - 2
-6x + 6 = 5x
+6x +6x
6 = 11x
/11 /11
6/11 = x
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Answer with explanation:
The given differential equation is
y" -y'+y=2 sin 3x------(1)
Let, y'=z
y"=z'

Substituting the value of , y, y' and y" in equation (1)
z'-z+zx=2 sin 3 x
z'+z(x-1)=2 sin 3 x-----------(1)
This is a type of linear differential equation.
Integrating factor

Multiplying both sides of equation (1) by integrating factor and integrating we get


I hope this helps you
if 18 gallons for 420 miles
? gallons for 357 miles
?.420=18.357
?=15,3
<span>The workers paved 2/5 miles in 1 hour =)</span>