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jenyasd209 [6]
3 years ago
12

What is the equation of the line that passes through the point (-5,7) and has a slope of -2/5

Mathematics
2 answers:
Pie3 years ago
7 0

Answer:

The equation of a line that passes through the point (-5,7) and has a slope of -2/5 would be y = -2/5x + 5

Step-by-step explanation:

In the math term <em>y = mx + b</em>, "m" represents slope. So you can just substitute it for -2/5. "b" represents the y-intercept. 5 is the only number that works, so you just substitute "b" for 5.

RideAnS [48]3 years ago
7 0
Bddskdksmsnnd76bsbabah
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1. A sine function has the following key features:
andrew11 [14]
Problem 1

See the attached image (figure 1)

16pi seems like a typo. I'm going to assume that it's a fraction and it is 1/(6pi)
f = 1/(6pi) = frequency
T = 1/f = 1/(1/(6pi)) = 6pi
Amplitude = 2
a = 2
b = 2pi/T = 2pi/(6pi) = 1/3
Midline: y = 3
d = 3

The function is
y = a*sin(bx-c)+d
y = 2*sin(1/3*x-0)+3
y = 2*sin(x/3)+3

===============================================

Problem 2

See the attached image (figure 2) 

T = 12 is the period
a = 4 is the amplitude
b = 2pi/T = 2pi/12 = pi/6
y = 1 is the midline so d = 1
The y intercept is (0,1) which is the midline, which indicates no phase shifts have occurred so c = 0

The function is
y = a*sin(bx-c)+d
y = 4*sin((pi/6)x-0)+1
y = 4*sin((pi/6)x)+1

===============================================

Problem 3

See the attached image (figure 3)

Period = 4pi
T = 4pi
b = 2pi/T = 2pi/(4pi) = 1/2 = 0.5
Amplitude = 2
a = 2
Midline: y = 3
d = 3
y-intercept: (0,3)
The function is a reflection of its parent function over the x-axis, so 'a' is negative meaning a = -2 instead of a = 2

The function is
y = a*sin(bx-c)+d
y = -2*sin(0.5x-0)+3
y = -2*sin(0.5x)+3

===============================================

Problem 4

See the attached image (figure 4)

a = 10 which is half of the distance between the highest and lowest points
T = 8 is the period
b = 2pi/T = 2pi/8 = pi/4
c = -pi/2 is the phase shift since its really a cosine graph
d = 0 is the midline

The function is
y = a*sin(bx-c)+d
y = 10*sin((pi/4)*x+(-pi/2))+0
y = 10*sin((pi/4)*x+pi/2)

===============================================

Problem 5

See the attached image (figure 5)

a = 2 is the amplitude since it bobs up and down this distance from the midline
T = 8 seconds is the period (double that of the time it takes for it to go from the highest to the lowest point)
b = 2pi/T = 2pi/8 = pi/4
c = 0 is the phase shift as the buoy starts at normal depth of 20 meters
d = 20 is the midline

The function is
y = a*sin(bx-c)+d
y = 2*sin((pi/4)x-0)+20
y = 2*sin((pi/4)x)+20

===============================================

8 0
2 years ago
Read 2 more answers
Hey !! Can someone please help me with this??
Katyanochek1 [597]

Answer:

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Step-by-step explanation:

4 to the third power, is the same as 4 x 4 x 4.

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<em>Hope this helps and have a nice day!! :) :] :D</em>

7 0
2 years ago
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kicyunya [14]

Answer:

A. 2 terms; variable = x; constant = 4.5 -------> 4.5 - 2x

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D. 3 terms; variables = x and y; constant = 3 --------------> x - 2y + 3

Its 100% correct just not in the order you put it in, I think you might of switched them but I just did the Warm-Up and its right my dudes :)

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3 years ago
Which postulate or theorem proves that these two triangles are congruent?
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Answer:

SAS congruence postulate. sweetheart.

Step-by-step explanation:


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2 years ago
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Given:
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3 years ago
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