Answer:
2x + y - 1 = 0
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Given
x - 2y + 4 = 0 ( subtract x + 4 from both sides )
- 2y = - x - 4 ( divide all terms by - 2 )
y = 
x + 2 ← in slope- intercept form
with slope m =
Given a line with slope m then the slope of a line perpendicular to it is
= - 
= - 
= - 2 , thus
y = - 2x + c ← is the partial equation of the perpendicular line
To find c substitute (1, - 1) into the partial equation
- 1 = - 2 + c ⇒ c = - 1 + 2 = 1
y = - 2x + 1 ← in slope intercept form
Subtract - 2x + 1 from both sides
2x + y - 1 = 0 ← in general form
Answer:
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Answer:
Step-by-step explanation:
We are given f(x) and g(x)
1. (f+g)(x)
(f+g)(x) = f(x) + g(x)
= 
= 
Domain : All real numbers as it there exists a value of (f+g)(x) f every x .
2. (f-g)(x)
(f-g)(x) = f(x)-g(x)
= 
=
Domain : All real numbers as it there exists a value of (f-g)(x) f every x .
Part 3 .
Domain : In this case we see that the function is not defined for values of x for which the denominator becomes 0 or less than zero . Hence only those values of x are defined for which
or 
Hence taking square roots on both sides and solving inequality we get.
The correct answer is C 20
Answer:
step 4
Step-by-step explanation:
because y is equation 2 is -y so the sign should have changed for -2x it should have been +2x since - and - equals to +
