The greater fraction is 6/11
6/11 = 0.54
1/2 = 0.50
Therefore 0.54 which is 6/11 is greater
Answer:
First blank: $5
Second blank: $7.50
Third blank: $11.25
Fourth blank: $13.5
Fifth blank: $15.75
Sixth blank: $18.00
Step-by-step explanation:
Half a number is $2.25, so multiply 2.25 times each half.
First blank:$2.25*2=$5.00
Second blank: $2.25*3=$7.50
Third blank: $2.25*5=$11.25
Fourth blank: $2.25*6=13.50
Fifth blank: $2.25*7=$15.75
Sixth blank: $2.25*8=$18.00
Y = 3x - 4.....the slope here is 3. A perpendicular line will have a negative reciprocal slope. To find the negative reciprocal, u flip the slope and change the sign. So we will need a slope of -1/3...see how I flipped the slope of 3/1 and made it 1/3...and then changed the sign, making it -1/3.
y = mx + b
slope(m) = -1/3
(2,1)...x = 2 and y = 1
now we sub and find b, the y int
1 = -1/3(2) + b
1 = -2/3 + b
1 + 2/3 = b
3/3 + 2/3 = b
5/3 = b
so ur perpendicular equation is : y = -1/3x + 5/3
Answer:
95% confidence interval for the mean number of months is between a lower limit of 6.67 months and an upper limit of 25.73 months.
Step-by-step explanation:
Confidence interval is given as mean +/- margin of error (E)
Data: 5, 15, 12, 22, 27
mean = (5+15+12+22+27)/5 = 81/5 = 16.2 months
sd = sqrt[((5-16.2)^2 + (15-16.2)^2 + (12-16.2)^2 + (22-16.2)^2 + (27-16.2)^2) ÷ 5] = sqrt(58.96) = 7.68 months
n = 5
degree of freedom = n-1 = 5-1 = 4
confidence level (C) = 95% = 0.95
significance level = 1 - C = 1 - 0.95 = 0.05 = 5%
critical value (t) corresponding to 4 degrees of freedom and 5% significance level is 2.776
E = t×sd/√n = 2.776×7.68/√5 = 9.53 months
Lower limit of mean = mean - E = 16.2 - 9.53 = 6.67 months
Upper limit of mean = mean + E = 16.2 + 9.53 = 25.73 months
95% confidence interval is (6.67, 25.73)
