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alex41 [277]
2 years ago
11

Can some body help me

Mathematics
1 answer:
maksim [4K]2 years ago
6 0

Answer:

63

Step-by-step explanation:

k=y/x

y/x=k

y=k×x

y=7×9

y=63

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Can anyone help with this?
PilotLPTM [1.2K]

Answer:

46

Step-by-step explanation:

The complete square starting with x^2+14x would be x^2+14x+49, since the square would be (x+7)^2. To make this square perfect, then, you would need to add 46 to make 49 with the 3. Hope this helps!

6 0
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Y=2x-5<br> 4x-y=7 what is the value of x
amid [387]

Answer:

x=1 and y=-3

Step-by-step explanation:

hope this helped :)

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3 years ago
Paulo works at the United Nations. He researched what percent of the world's population lives on each continent. He surveys a sa
Fofino [41]

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confidence interval using a  two sample t test between percents

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5 0
2 years ago
What number must you add to complete the square x2 + 12x = -3
Serga [27]
<span>What number must you add to complete the square x^2 + 12x = -3?</span>

Make sure to always check your answers, by the way!

The answer is: (x + 6)² - 33


Hope I helped!

Let me know if you need anything else!

~ Zoe
6 0
3 years ago
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HELP with these questions
zlopas [31]

<u>Step-by-step explanation:</u>

transform the parent graph of f(x) = ln x        into f(x) = - ln (x - 4)  by shifting the parent graph 4 units to the right and reflecting over the x-axis

(???, 0): 0 = - ln (x - 4)

            \frac{0}{-1} = \frac{-ln (x - 4)}{-1}

            0 = ln (x - 4)

            e^{0} = e^{ln (x - 4)}

             1 = x - 4

          <u> +4 </u>  <u>    +4 </u>

             5 = x

(5, 0)

(???, 1): 1 = - ln (x - 4)

            \frac{0}{-1} = \frac{-ln (x - 4)}{-1}

            1 = ln (x - 4)

            e^{1} = e^{ln (x - 4)}

             e = x - 4

          <u> +4 </u>   <u>    +4 </u>

         e + 4 = x

          6.72 = x

(6.72, 1)

Domain: x - 4 > 0

                <u>  +4 </u>  <u>+4  </u>

               x       > 4

(4, ∞)

Vertical asymptotes: there are no vertical asymptotes for the parent function and the transformation did not alter that

No vertical asymptotes

*************************************************************************

transform the parent graph of f(x) = 3ˣ        into f(x) = - 3ˣ⁺⁵  by shifting the parent graph 5 units to the left and reflecting over the x-axis

Domain: there is no restriction on x so domain is all real number

(-∞, ∞)

Range: there is a horizontal asymptote for the parent graph of y = 0 with range of y > 0.  the transformation is a reflection over the x-axis so the horizontal asymptote is the same (y = 0) but the range changed to y < 0.

(-∞, 0)

Y-intercept is when x = 0:

f(x) = - 3ˣ⁺⁵

      = - 3⁰⁺⁵

      = - 3⁵

      = -243

Horizontal Asymptote: y = 0  <em>(explanation above)</em>

5 0
3 years ago
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