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alexdok [17]
3 years ago
13

HELP; The life spans of 10 adult mayflies have a mean of 4 hours and a MAD of 2 hours. Fill in the table below with possible val

ues for the life spans. You can use the same values more than once. Can any one of the 10 mayflies in the group live for 1 full day? Justify your answer.

Mathematics
1 answer:
lord [1]3 years ago
7 0

Step-by-step answer:

Assuming MAD stands for mean absolute deviation (2 hours), then the total absolute deviation from the mean (4 hours) is 10*2=20 hours.

If one of the flies live for 1 full day, the absolute deviation is 24-4=20 hours.  This automatically requires the other flies live exactly 4 hours to have the MAD equal to 20 hours.  

However, the above arrangement does not give a mean of 4 hours, but a mean of (24+9*4)/10=6 hours. This means that it is not possible to have a fly living for a full day.

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Answer:

i like cheese wbu hahahahahaha

5 0
3 years ago
Q3. Express 984. 6080 correct to
const2013 [10]

Answer:

a) 984.6080 = 984.61 to 2 decimal places

b) 984.6080 = 984.6 to 4 significant figures

c) 984.6080 = 984.608 to 3 decimal places

d) 984.6080 = 984.61 to the nearest hundredth

Step-by-step explanation:

Answers to the approximation questions above are supplied below.

First, you needs to know approximation processes:

Step 1: Keep the required number of digits in question.

Step 2: Before rounding off the remaining digits, look at the next digit to the required number of accuracy, if it is 5 or more, increase the last digit of the number you're keeping by 1, otherwise leave it as it is and round down to zero all the unwanted digits.

Similarly, there is need know the meaning of each degree of accuracy.

1. Decimal places: These are the number of digits occurring after the decimal point. E.g. a set of figures in 1 decimal place has only one digit after decimal point, i.e. 65.4. In the case of the question above,

a) 984.6080 = 984.61 to 2 decimal places

c) 984.6080 = 984.608 to 3 decimal places

2. Significant figures: Basically, these are nonzero digits in a set of figures. However, when zero is in the middle of nonzero digits, i.e, 3045, such zero is a significant figure. In the question above,

b) 984.6080 = 984.6 to 4 significant figures

3. Hundredth: Under place value system, hundredth of a set of figures is located at two digits after the decimal point. In other words, hundredth is same as two decimal places so the same approach is required for the two. Thus;

d) 984.6080 = 984.61 to the nearest hundredth

You can see that the result for both 2 decimal places and nearest hundredth are the same, that is, 984.6080 = 984.61 to 2 decimal places and to the nearest hundredth respectively.

Therefore, the answers are summarized thus:

a) 984.6080 = 984.61 to 2 decimal places

b) 984.6080 = 984.6 to 4 significant figures

c) 984.6080 = 984.608 to 3 decimal places

d) 984.6080 = 984.61 to the nearest hundredth

5 0
3 years ago
Read 2 more answers
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Answer:

Sabemos que:

L es el largo de la avenida.

En la primer etapa se asfalto la mitad, L/2, entonces lo que queda por asfaltar es:

L - L/2 = L/2.

En la segunda etapa se asfalto la quinta parte, L/5, entonces lo que queda por asfaltar es:

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En la tercer etapa se asfalto la cuarta parte del total, L/4, entonces lo que queda por asfaltar es:

(3/10)*L - L/4 = 12*L/40 - 10L/40 = (2/40)*L

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tatiyna

x^2+6x-5=0

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2x+6x-5=0

2x+6x=8x

8x-5=0

+5 +5

(if you don’t know what I’m doing here is that I’m removing the negative 5 by putting a positive 5 since both of them make 0. Also the “x” always stay alone and the unit stays as the unit)

(I putted the positive under the 0 because what u do to the unit you need to do the same thing with the other.)

8x/8=5/8

(If ur lost here it means dividing.)

The answer

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