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Lyrx [107]
3 years ago
8

I have X, I just need Y.

Mathematics
1 answer:
GarryVolchara [31]3 years ago
6 0

I'm getting x = 9.3223 which rounds to 9.32. Nice work.

Once you know the value of x, you can use the law of sines to find the value of y

sin(A)/a = sin(B)/b

sin(y)/7 = sin(70)/x

sin(y)/7 = sin(70)/9.3223

sin(y) = 7*(sin(70)/9.3223)

sin(y) = 0.70560358983312

y = arcsin(0.70560358983312)

y = 44.8783278056846

<h3>y = 44.88 approximately</h3>

------------------------------

If you must use the law of cosines, then here's how you could do it

c^2 = a^2 + b^2 - 2*a*b*cos(C)

7^2 = x^2 + 9^2 - 2*x*9*cos(y)

7^2 = (9.3223)^2 + 9^2 - 2*9.3223*9*cos(y)

49 = 86.90527729+81-167.8014cos(y)

49 = 167.90527729-167.8014cos(y)

-167.8014cos(y) = 49-167.90527729

-167.8014cos(y) = -118.90527729

cos(y) = -118.90527729/(-167.8014)

cos(y) = 0.708607182598

y = arccos(0.708607182598)

y = 44.8782954209662 ... this is slightly different from before due to rounding error

<h3>y = 44.88 approximately</h3>
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Answer:

<u>The correct answer is B. ∠X = 28.6°, ∠Y = 31.2°, ∠Z = 120.2°</u>

Step-by-step explanation:

Let's recall that for solving a SSS triangle, we :

1. Use the Law of Cosines first to calculate one of the angles

2. Use The Law of Cosines again to find another angle

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1. Cos x = (9² + 15² - 8.3²/2 * 9 * 15)

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3. z = 180 - 31.2 - 28.6

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<u>The correct answer is B. ∠X = 28.6°, ∠Y = 31.2°, ∠Z = 120.2°</u>

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<u>Solution-</u>

From the figure,

AE = 2.4

EB = 2.8

BC = 11.7


Area of rectangle 1 = 8.68 sq.in

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\Rightarrow EB \times HI=8.68  (∵ sides of the rectangle 2)

\Rightarrow 2.8 \times HI=8.68

\Rightarrow HI=3.1


Area of Triangle 1 = 6.48 sq.in

\Rightarrow \frac{1}{2}\times AE \times EG= 6.48

\Rightarrow \frac{1}{2}\times AE \times (EF+FG)= 6.48

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BC = BH+HI+IC

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The area of Rectangle 2,

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The area of Triangle 2,

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The area of the whole figure = Area of Triangle 1 + Area of rectangle 1 + Area of Triangle 2 + Area of rectangle 2

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