4/1 is the slope so (-2-1/4=x)
To be able to compare two fraction we have to make common denominator. Then we can compare fractions.
Now we can compare
1/2 is bigger than 5/16
A=-32 (acceleration is the constant g) integrating with respect to t
v=-32t+vi but initial velocity is equal to zero as it is just "dropped".
h=-32t^2/2+hi, since the initial height is 144 ft
h(t)=-16t^2+144
The object will be at the ground when h(t)=0
-16t^2+144
-16(t^2-9)=0
-16(t+3)(t-3)=0, but since we know t>0
t=3 seconds.
Answer:
x>1
Step-by-step explanation:
Make a line put number like
__________|____________________
-4 -3 -2 -1 0 1 2 3 4 5 6 7 8 9 10
Let "a" and "b" be some number where:
a - b = 24
We want to find where a^2 + b^2 is a minimum. Instead of just logically figuring out that the answer is where a=b=12, I'll just use derivatives.
So we can first substitute for "a" where a = b+24
So we have (b+24)^2 + b^2 = b^2 +48b +576 + b^2
And that equals 2b^2 +48b +576
Then we take the derivative and set it equal to zero:
4b +48 = 0
4(b+12) = 0
b + 12 = 0
b = -12
Thus "a" must equal 12.
So:
a = 12
b = -12
And the sum of those two numbers squared is (12)^2 + (-12)^2 = 144 + 144 = 288.
The smallest sum is 288.
