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kotegsom [21]
4 years ago
5

Below are the results of tossing a number cube 9 times. Find the experimental probability of tossing an odd number. 4, 3, 6, 6,

2, 5, 3, 5, 1
A 4/9
B 1/2
C 5/9
D 2/3
Mathematics
1 answer:
My name is Ann [436]4 years ago
6 0

Answer: C. \dfrac{5}{9}

Step-by-step explanation:

Given: The results of tossing a number cube 9 times are:

4, 3, 6, 6, 2, 5, 3, 5, 1  

Then , the number of times get odd number (3,5,3,5,1): 5

Now, the experimental probability of tossing an odd number will be :

\text{P(odd)}=\dfrac{\text{Number odd results}}{\text{Total number of times coin tossed}}\\\\\Rightarrow\ \text{P(odd)}=\dfrac{5}{9}

Hence, the experimental probability of tossing an odd number \dfrac{5}{9}

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