What is 669 x 76 (SHOW YOUR WORK!!!!)
2 answers:
669 * 76
1. 6 times 9 is 54, so you bring down the 4 and then put a small '5' on top of the 6
2. 6 times 6 is 36, plus 5 is 41, so you bring down the 1 and put a small '4' on top of the other 6
3. 6 times 6 is 36, plus 4 is 40, so you bring down the 40, in which the first number will be 4,014. Afterwards, you bring down a '0' at the bottom of the number '4'
4. 7 times 9 is 63, so you bring down a '3' (put it next to the '0') and replace the number '5' with a small '6 (put it on top of the number '6')
5. 6 times 7 is 42, plus 6 is 48, so you bring down the '8' (put it next to the '3') (quick note: since there is already a number '4' on top of the '6', you don't have to replace it)
6. 6 times 7 is 42, plus 4 is 46, so you bring down that number. Therefore, the second number would be 46,830
So, in this case, you should have a problem written like this:
The answer to this problem is 50,844
1. 6 times 9 is 54, so you bring down the 4 and then put a small '5' on top of the 6
2. 6 times 6 is 36, plus 5 is 41, so you bring down the 1 and put a small '4' on top of the other 6
3. 6 times 6 is 36, plus 4 is 40, so you bring down the 40, in which the first number will be 4,014. Afterwards, you bring down a '0' at the bottom of the number '4'
4. 7 times 9 is 63, so you bring down a '3' (put it next to the '0') and replace the number '5' with a small '6 (put it on top of the number '6')
5. 6 times 7 is 42, plus 6 is 48, so you bring down the '8' (put it next to the '3') (quick note: since there is already a number '4' on top of the '6', you don't have to replace it)
6. 6 times 7 is 42, plus 4 is 46, so you bring down that number. Therefore, the second number would be 46,830
So, in this case, you should have a problem written like this:
The answer to this problem is 50,844
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Answer:
a) 0.283 or 28.3%
b) 0.130 or 13%
c) 0.4 or 40%
d) 30.6 mm
Step-by-step explanation:
z-score of a single left atrial diameter value of healthy children can be calculated as:
z= where
- X is the left atrial diameter value we are looking for its z-score
- M is the mean left atrial diameter of healthy children (26.7 mm)
- s is the standard deviation (4.7 mm)
Then
a) proportion of healthy children who have left atrial diameters less than 24 mm
=P(z<z*) where z* is the z-score of 24 mm
z*= ≈ −0.574
And P(z<−0.574)=0.283
b) proportion of healthy children who have left atrial diameters greater than 32 mm
= P(z>z*) = 1-P(z<z*) where z* is the z-score of 32 mm
z*= ≈ 1.128
1-P(z<1.128)=0.8703=0.130
c) proportion of healthy children have left atrial diameters between 25 and 30 mm
=P(z(25)<z<z(30)) where z(25), z(30) are the z-scores of 25 and 30 mm
z(30)= ≈ 0.702
z(25)= ≈ −0.362
P(z<0.702)=0.7587
P(z<−0.362)=0.3587
Then P(z(25)<z<z(30)) =0.7587 - 0.3587 =0.4
d) to find the value for which only about 20% have a larger left atrial diameter, we assume
P(z>z*)=0.2 or 20% where z* is the z-score of the value we are looking for.
Then P(z<z*)=0.8 and z*=0.84. That is
0.84= solving this equation for X we get X=30.648