Answer: -69q+74
Step by step:
1. Use distributive property.
8⋅10+8(−6q) + 3(−7q − 2)
Multiply 8 • 10 then -6 • 8
80 - 48q + 3(-7q - 2)
2. Use distributive property again.
80 - 48q + 3(-7q - 2)
Multiply -7 • 3 then 3 • -2
80 - 48q -21q - 6
3. Simplify
Subtract 6 from 80 then subtract 21q from -48q.
-69q + 74
8(10 - 6q) + 3(-7q - 2) = -69q + 74
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I hope this answers your question. :)
Answer:
(3x^2 - 1)(3x^2 + 1)(9x^4 + 1).
Step-by-step explanation:
Using the identity for the difference of 2 squares;
a^2 - b^2 = (a - b)(a + b)
we put a^2 = 81x^8 and b^2 = 1 giving
a = 9x^4 and b = 1, so:
81x^8 − 1 = (9x^4 - 1)(9x^4 + 1)
Applying the difference of 2 squares to 9x^4 - 1:
= (3x^2 - 1)(3x^2 + 1)(9x^4 + 1).
Step 2 because he/she took out the parentheses when he/she wasn’t supposed to!
