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nordsb [41]
3 years ago
15

Factor completely 81x8 − 1. (9x4 − 1)(9x4 + 1) (3x2 − 1)(3x2 + 1)(9x4 − 1) (3x2 − 1)(3x2 + 1)(9x4 + 1) (3x2 − 1)(3x2 + 1)(3x2 +

1)(3x2 + 1)
Mathematics
1 answer:
denis-greek [22]3 years ago
6 0

Answer:

(3x^2 - 1)(3x^2 + 1)(9x^4 + 1).

Step-by-step explanation:

Using the identity for the difference of 2 squares;

a^2 - b^2 = (a - b)(a + b)  

we put a^2 = 81x^8 and b^2 = 1  giving

a = 9x^4 and b = 1, so:

81x^8 − 1 =   (9x^4 - 1)(9x^4 + 1)

Applying the difference of 2 squares to 9x^4 - 1:

= (3x^2 - 1)(3x^2 + 1)(9x^4 + 1).

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A^2 + b^2 = c^2      12^2 +16^2= c^2  C =400 so we square that and get the third side which is  20
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In right triangle RST below, altitude SV is drawn to
Brilliant_brown [7]

Answer:

ST = 12.2

Step-by-step explanation:

See the attached diagram of the triangle.

Here, Δ RST, Δ RSV and Δ STV all are right triangles.

If we assume that, ST = x and SR = y, then

From Δ RSV and Δ STV we get,

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Now, from Δ RST, we have

ST² + SR² = RT²

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Now, adding equations (1) and (2) we get,

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5 0
4 years ago
Can you anser the question number 7
goldfiish [28.3K]

Answer:

Length of rectangle = 64 inches

Width of rectangle = 32 inches

Step-by-step explanation:

Perimeter of rectangle = 192 in

Length = x

Width = \frac{1}{2}x

We need to find the length and width.

The formula used is: Perimeter\:of\:rectangle=2(Length+Width)

Putting values and finding value of x

Perimeter\:of\:rectangle=2(Length+Width)\\192=2(x+\frac{x}{2} )\\192=2(\frac{2x+x}{2} )\\192=2(\frac{3x}{2} )\\192=3x\\x=\frac{192}{3}\\x=64

So, we get x = 64

The length of rectangle x = 64

The width of rectangle = \frac{1}{2}x = \frac{64}{2} = 32

So, Length of rectangle = 64 inches

Width of rectangle = 32 inches

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3 years ago
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