Lets think they have cards, Alex = x , Gil = y and Meg = z. Then,
x+y+z = 740
Alex had 20 fewer cards than Gil. So,
x+20 = y
Alex had 120 fewer cards than Meg. So,
x+120 = z
x+(x+20)+(x+120) = 740
3x + 140 = 740
x= 200
y= 220
z= 320
<span>So Alex had 200 cards, Gil had 220 cards and Meg had 340 cards</span>
It's a degree, however in algebra there are also radians and gradians
Answer
4.8 x 10^-3
Step-by-step explanation:
Answer:
no
Step-by-step explanation:
(x, y)
(-1, 4)
4 < 2(-1) + 5
4 < -2 + 5
4 < 3
not true
Infinitely many ways!
Suppose you have the fraction 2/d.
<span>Pick </span>any<span> pair of integers a and b where b ≠ 0.</span>
Then 2b-ad is and integer, as is bd so that (2b - ad)/bd is a fraction.
Consider the fractions a/b and (2b - ad)/bd
<span>Their sum is </span>
a/b + (2b-ad)/bd = ad/bd + (2b-ad)/bd = 2b/bd = 2/d - as required.
<span>Since a and b were chosen arbitrarily, there are infinitely many possible answers to the question.</span>
