Use substitution to solve the system of linear equations. In your final answer, include all of your work.

1 answer:

4 0

Replace 'y' with -3x+4

$x + \frac{1}{3} (-3x+4) = \frac{4}{3} \\ \\ x -x + \frac{4}{3} = \frac{4}{3} \\ \\ \frac{4}{3} = \frac{4}{3}$

The variable 'x' cancels out, leaving the True statement 4/3 = 4/3
This means that the 2 equations are identical regardless of what x and y are.

Answer: System is consistent and dependent, there are an infinite number of solutions.

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arsen [322]

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3 years ago

The perimeters of the square and the triangle shown below are equal. What is the value of x?

Rudiy27

Perimeter is the sum of all the sides. So we can set up an equation:

$\sf 3x+1+3x+1+3x+1+3x+1=2x+8+x+8+4x+2$

Now solve for 'x', combine like terms:

When it comes to terms with variables it's just like normal addition but we keep the variable:

$\sf 3x+3x+3x+3x=12x$
$\sf 2x+x+4x=7x$

So we have:

$\sf 12x+1+1+1+1=7x+8+8+2$

Add:

$\sf 12x+4=7x+18$

Subtract 7x to both sides:

$\sf 5x+4=18$

Subtract 4 to both sides:

$\sf 5x=14$

Divide 5 to both sides:

$\boxed{\sf x=2.8}$