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professor190 [17]
2 years ago
8

Someone please help me .

Mathematics
1 answer:
horrorfan [7]2 years ago
3 0

Answer:

c)  r = 4x + 2y

Step-by-step explanation:

∑y

-3 + 5 =2

∑x

1 + 3 = 4

                           r = 4x + 2y

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Which statement is NOT true in the equation y = 9x?
slamgirl [31]

Answer:

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7 0
3 years ago
Can some hell me understand foil <br> for (4x-3)(x+11)
Naddik [55]

Answer:

4x² + 41x - 33

Step-by-step explanation:

  • F in foil stands for 'first'; take the first value in each bracket and multiply them together. So 4x × x = 4x²
  • O in foil stands for 'outside'; take the outermost values from each bracket and multiply them together. So 4x × 11 = 44x
  • I in foil stands for 'inside'; take the innermost values for each bracket and multiply them together. So -3 × x = -3x
  • Finally, L in foil stands for 'last'; take the last value in each bracket and multiply them together. So -3 × 11 = -33
  • Now, we can put this all together and simplify: 4x² + 44x - 3x - 33 → 4x² + 41x - 33.

Hope this helps!

7 0
2 years ago
Suppose for some value of x the solution to the equation 2.5(y−x)=0 is y = 6. What must be true about x?
Varvara68 [4.7K]

Step-by-step explanation:

In this case, you input the value of y (y = 6) into the equation ( 2.5(y-x)= 0)

2.5(6-x) = 0

Open the bracket,

(2.5×6)-2.5x= 0

Collect like terms.

2.5x= 2.5×6

Divide both sides by the coefficient of x (2.5)

x = 6

So,

x= 6 is true.

.

Substituting 6 for x in the equation,

2.5(6-6)= 0

2.5•0 = 0

0= 0

Which is also true.

7 0
2 years ago
Line segments JK and JL in the xy-coordinate plan both have a common endpoint J(-4,11) and midpoints at M1 (2,16) and M2 (-3,5),
OleMash [197]
The first part of the question is not needed 
we only need to know M1 and M2
(y2-y1)^2+(x2-x1)^2=(your answer)^2
(5-16)^2+(-3-2)^2=(your answer)^2
(-11)^2+(-5)^2=(your answer)^2
121+25=(your answer)^2
146=(your answer)^2
√146=12.0830459735945721
nearest tenth=12.1
6 0
3 years ago
Question 4 of 17
Vlada [557]

Answer:

I think it is A OR D

4 0
2 years ago
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