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2 years ago

Someone please help me .

Mathematics

1 answer:

horrorfan [7]2 years ago

3 0

Answer:

c) r = 4x + 2y

Step-by-step explanation:

∑y

-3 + 5 =2

∑x

1 + 3 = 4

r = 4x + 2y

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2.25x + 15 = 9.5x + 0.5

natulia [17]

Answer:

x=2

Step-by-step explanation:

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3 years ago

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If 64 feet of rope weighs 20 pounds how much will 80 feet of the same type of rope weigh?

worty [1.4K]

Answer:

25 pounds, hope its right

Step-by-step explanation

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3 years ago

Solve the following quadratic equation for all values of x in simplest form. (x-4)^2=33

Brrunno [24]

$\huge\text{$x=\boxed{\sqrt{33}+4,\ -\sqrt{33}+4}$}$

To solve for $x$ , we need to isolate it on one side of the equation.

Take the square root of both sides, making sure to use both positive and negative roots.

$\begin{aligned}(x-4)^2&=33\\x-4&=\pm\sqrt{33}\end{aligned}$

$\sqrt{33}$ cannot be simplified, so we'll leave it as-is.

Add $4$ to both sides to fully isolate $x$ .

$x=\pm\sqrt{33}+4$

Expand the solution by making two solutions, one where $\sqrt{33}$ is positive and one where it's negative.

$x=\sqrt{33}+4,\ x=-\sqrt{33}+4\\x=\boxed{\sqrt{33}+4,\ -\sqrt{33}+4}$

5 0

2 years ago

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Given: ∆PQR, m∠R = 90° m∠PQR = 75° M ∈ PR , MP = 18 m∠MQR = 60° Find: RQ

tensa zangetsu [6.8K]

Answer: RQ= 8.99 ( approx)

Step-by-step explanation:

Let MR= x

Since, In triangle, PRQ, tan 75°= $\frac{18+x}{RQ}$

⇒ RQ= $\frac{18+x}{tan 75^{\circ}}$

Now, In triangle MRQ,

tan 60°= $\frac{18+x}{RQ}$

⇒ RQ= $\frac{x}{tan 60^{\circ}}$

On equating both values of RQ,

$\frac{18+x}{tan 75^{\circ}}=\frac{x}{tan 60^{\circ}}$

⇒ $\frac{18+x}{x}=\frac{tan 75^{\circ}}{tan 60^{\circ}}$

⇒ $\frac{18+x}{x}=2.15470053838$

⇒ $18=2.15470053838x-x$

⇒ $x=15.5884572681$ ≈15.60

Thus RQ=8.99999999999≈8.99

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3 years ago

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DochEvi [55]

Answer:

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Step-by-step explanation:

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