1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
BigorU [14]
3 years ago
13

Convert 20 mm into km​

Mathematics
1 answer:
andrew-mc [135]3 years ago
3 0

Answer:

Step-by-step explanation:

1 km = 1,000 m = 100,000 cm = 1,000,000 mm

1 mm is millionth part of 1 km

1 mm = 0.000001 km

20 mm = 0.00002 km

You might be interested in
Solve these for me please <br><br> 4x+7x-2+5x-10=180 i need to know the degrees
k0ka [10]

x=12

48, 84 and 60

youre welcome

5 0
3 years ago
Suppose you invest $2000 at a rate of 3.25% continuously, determine the worth of the investment after 10 years.
AysviL [449]

Answer:

$2650

Step-by-step explanation:

= 2000 × 0.0325 × 10 = 650

= $ 650.00

8 0
3 years ago
What is the area of the shaded region?<br> 3.3 km<br> 3 km
nasty-shy [4]

Answer: 9.9

Step-by-step explanation:

When you multiply, take away the decimal. Then, it's 33 times 3. 33 times 3 is 99, so then you put the decimal back.

5 0
3 years ago
Which statement best describes the function?
madam [21]

Answer:

Its D

Step-by-step explanation:

7 0
2 years ago
Consider an experiment that consists of recording the birthday for each of 20 randomly selected persons. Ignoring leap years, we
8_murik_8 [283]

Answer:

a)  p_{20d} = 0.588

b) 23

c) 47

Step-by-step explanation:

To find a solution for this question we must consider the following:

If we’d like to know the probability of two or more people having the same birthday we can start by analyzing the cases with 1, 2 and 3 people

For n=1 we only have 1 person, so the probability  p_{1} of sharing a birthday is 0 (p_{1}=0)

For n=2 the probability p_{2} can be calculated according to Laplace’s rule. That is, 365 different ways that a person’s birthday coincides, one for every day of the year (favorable result) and 365*365 different ways for the result to happen (possible results), therefore,

p_{2} = \frac{365}{365^{2} } = \frac{1}{365}

For n=3 we may calculate the probability p_{3} that at least two of them share their birthday by using the opposite probability P(A)=1-P(B). That means calculating the probability that all three were born on different days using the probability of the intersection of two events, we have:

p_{3} = 1 - \frac{364}{365}*\frac{363}{365} = 1 - \frac{364*363}{365^{2} }

So, the second person’s birthday might be on any of the 365 days of the year, but it won’t coincide with the first person on 364 days, same for the third person compared with the first and second person (363).

Let’s make it general for every n:

p_{n} = 1 - \frac{364}{365}*\frac{363}{365}*\frac{362}{365}*...*\frac{(365-n+1)}{365}

p_{n} = \frac{364*363*362*...*(365-n+1)}{365^{n-1} }

p_{n} = \frac{365*364*363*...*(365-n+1)}{365^{n} }

p_{n} = \frac{365!}{365^{n}*(365-n)! }

Now, let’s answer the questions!

a) Remember we just calculated the probability for n people having the same birthday by calculating 1 <em>minus the opposite</em>, hence <em>we just need the second part of the first calculation for</em> p_{n}, that is:

p_{20d} = \frac{364}{365}*\frac{363}{365}*\frac{362}{365}*...*\frac{(365-20+1)}{365}

We replace n=20 and we obtain (you’ll need some excel here, try calculating first the quotients then the products):

p_{20d} = 0.588

So, we have a 58% probability that 20 people chosen randomly have different birthdays.

b) and c) Again, remember all the reasoning above, we actually have the answer in the last calculation for pn:

p_{n} = \frac{365!}{365^{n}*(365-n)! }

But here we have to apply some trial and error for 0.50 and 0.95, therefore, use a calculator or Excel to make the calculations replacing n until you find the right n for p_{n}=0.50 and p_{n}=0.95

b) 0.50 = 365!/(365^n)*(365-n)!

n           p_{n}

1              0

2           0,003

3           0,008

….           …

20           0,411

21           0,444

22           0,476

23           0,507

The minimum number of people such that the probability of two or more of them have the same birthday is at least 50% is 23.

c) 0.95 = 365!/(365^n)*(365-n)!

We keep on going with the calculations made for a)

n             p_{n}

…                …

43            0,924

44            0,933

45            0,941

46            0,948

47            0,955

The minimum number of people such that the probability of two or more of them have the same birthday is at least 95% is 47.

And we’re done :)

6 0
4 years ago
Other questions:
  • 3^x= 3^2 <br> The ^ means Exponet
    12·1 answer
  • A flock of Canadian geese migrated 1623 miles in 28 days. What was the average rate at which these geese traveled in miles per d
    13·1 answer
  • 20 pts-------
    6·1 answer
  • david is building a wooden picture frame. each frame requers 3/4 feet of wood. If david started with 12 feet and now has 6 feet
    9·1 answer
  • Find the slant height of the cone. Round to the nearest tenth.
    14·2 answers
  • Number n is 25 less than 120% of itself. What is the value of n?
    5·1 answer
  • A random sample of 77 fields of durum wheat has a mean yield of 27.427.4 bushels per acre and standard deviation of 5.755.75 bus
    6·1 answer
  • The perimeter of the square below is 36 yards. What is the length of each side?
    5·2 answers
  • In the diagram, parallel lines P and Q are cut by transversal R.
    13·1 answer
  • The fragment of a function given by the formula y = ax ^ 2 passes through the points of the coordinate plane (-3; 18) and (1; c)
    7·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!