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3 years ago

What is the answer?please help me

Mathematics

1 answer:

Maslowich3 years ago

6 0

Answer:

y = 2x - 1 Graph B

y = 2x + 2 Graph A

y = 2x - 5 Graph C

Step-by-step explanation:

y = mx + c

c is where the line intersect the Y axis.

<h2>Substitute x for 0:</h2>

y = 2x - 1

2 * 0 - 1 = -1.

This is graph B because it intersects at 0,-1.

y = 2x + 2

2 * 0 + 2 = 2

This is graph A because it intersects at 0,2.

y = 2x - 5

2 * 0 - 5 = -5

This is graph C because it intersects at 0,-5.

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3 years ago

What is the solution to the equation

Dafna11 [192]

$\sqrt{4t+5}=3-\sqrt{t+5}\\\\D:4t+5\geq0\ \wedge\ t+5\geq0\ \wedge\ \sqrt{t+5}\leq3\\\\t\geq-\dfrac{5}{4}\ \wedge\ t\geq-5\ \wedge\ t\leq6$

therefore
$D:x\in\left< -\dfrac{5}{4};\ 6\right>$

$\sqrt{4t+5}=3-\sqrt{t+5}\ \ \ |^2\\\\(\sqrt{4t+5})^2=(3-\sqrt{t+5})^2\ \ \ |use:(a-b)^2=a^2-2ab+b^2\\\\4t+5=3^2-2\cdot3\cdot\sqrt{t+5}+(\sqrt{t+5})^2\\\\4t+5=9-6\sqrt{t+5}+t+5\ \ \ \ |-t\\\\3t+5=14-6\sqrt{t+5}\ \ \ \ |-14\\\\3t-9=-6\sqrt{t+5}\ \ \ \ |change\ signs$
$9-3t=6\sqrt{t+5}\ \ \ \ |:3\\\\3-t=2\sqrt{t+5}\ \ \ \ |^2\\\\(3-t)^2=(2\sqrt{t+5})^2\\\\3^2-2\cdot3\cdot t+t^2=4(t+5)\\\\9-6t+t^2=4t+20\ \ \ |-4t-20\\\\t^2-10t-11=0\\\\t^2+t-11t-11=0\\\\t(t+1)-11(t+1)=0\\\\(t+1)(t-11)=0\iff t+1=0\ \vee\ t-11=0\\\\t=-1\in D\ \vee\ t=11\notin D$
Answer: t = -1.

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Answer:

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Step-by-step explanation:

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3 years ago

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ale4655 [162]

Answer:

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Step-by-step explanation:

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