Ask question

Ask question

All categories

2 years ago

14

Given h(x) =3x-4 find x if h(x) =17

1 answer:

NikAS [45]2 years ago

6 0

Answer:

x=7

Step-by-step explanation:

h(x) = 17 so you would input 17 for h(x). The equation should look like this. 17= 3x-4. Add 4 to both sides changing the equation to 21 = 3x. Finally divide both side by 3 and you should get x = 7.

You might be interested in

Use the formula to find the length of the radius if the area is 25 square centimeters.

Alexandra [31]

Answer:r = 2.81 centimeters

Step-by-step explanation:

The area of this circle can be found using the formula

A=πr^2

Where r = radius of the circle

π is a constant whose value is 3.14

We are given the area of the circle to be 25 square centimeters. To determine the length of the radius of the circle , we will make r the subject of the formula

r^2 = A/π

Taking square root of both sides of the equation,

r = √A/π

Since A = 25 and π = 3.14,

r= √25/3.14

r = 2.82166323992

Approximating to the nearest tenth of a centimeter,

r = 2.81 centimeters

5 0

3 years ago

What is the solution to the system below? <br> x + 3y = 0<br> 2x - y = -7

sasho [114]

( x, y ) = ( -3, 1 )

hope it helps!

8 0

3 years ago

How do you do this question?

IRINA_888 [86]

Answer:

.

Step-by-step explanation:

6 0

3 years ago

A carpenter wants to build a rectangular box with square sides in which to put round things. the material for the bottom costs $

alexira [117]

Answer: $1.627\times 1.627\times 1.88\ ft^3$

Step-by-step explanation:

Given

Suppose side face have a dimension of l\times l

and width of h

volume $V=l^2\cdot h$

$h=\frac{V}{l^2}$

volume $V=5 ft^3$

Area of side wall is $A_s=l^2$

Area of top Wall $A_t=l\times h$

Area of bottom $A_b=l\times h$

Cost of bottom wall $c_b=20\times l\times h=20lh$

Cost of top wall $c_t=50\times l\times h=50lh$

Cost of side walls $c_s=4\times l^2\times 10=40l^2$

total cost $C=c_s+c_t+c_b=20lh+50lh+40l^2$

$C=70lh+40l^2$

$C=70\times l\times \frac{5}{l^2}+40l^2$

differentiate C w.r.t l to get minima or maxima

$\frac{\mathrm{d} C}{\mathrm{d} l}=0$

$-\frac{350}{l}+80l^2=0$

$l^3=\frac{350}{80}$

$l=1.627 ft$

$h=\frac{5}{2.648}$

$h=1.88 ft$

Dimension of Box is $1.627\times 1.627\times 1.88\ ft^3$

5 0

3 years ago

Graph y−5=−23(x+9) using the point and slope given in the equation. Use the line tool and select two points on the line.

jarptica [38.1K]

Maybe try (-9, 6) and (-9,5)
i think it may be correct

7 0

3 years ago

Read 2 more answers