The answer is letter a. Hill terrain, hill slope, and hill elevation
Answer:
2.92 mol
Explanation:
Step 1: Write the balanced equation
2 B(s) + 6 HCI(aq) ⇒ 2 BCl₃(aq) + 3 H₂(g)
Step 2: Establish the appropriate molar ratio
The molar ratio of hydrochloric acid to boron chloride is 6:2.
Step 3: Calculate the moles of boron chloride produced from 8.752 moles of hydrochloric acid
<span>Unless otherwise stated, the common room
temperature and pressure is at 25°C and 1 atmosphere, respectively. At this
temperature and pressure hydrogen chloride is expected to be in a gaseous state.
Since it is a diatomic molecule consisting of hydrogen and chlorine atoms, they
have weak forces of interaction between molecules resulting to an uncondensed
state at room temperature. If the atmosphere where is it suspended has
moisture, hydrogen chloride gas is expected to react with the moisture to form
fumes of hydrochloric acid.</span>
Out of the following given choices;
A. O-linked; serine
B. O-linked; asparagine
C. O-linked; threonine
D. N-linked; glutamine
E. N-linked; asparagine
The answer is B. O-Linked referred to type of glycosylation of the proteins. This type of glycosylation involves attachment of a monosaccharide or an oligosaccharide molecule to an oxygen atom in an amino acid residue of proteins. While N-linked glycosylation is an attachment of an oligosaccharide molecule to an amide nitrogen atom of arginine or asparagine of proteins. Glycosylation (a post-transcriptional modification) is a bond formed from donor of a glycosyl group (usually a carbohydrate ) and a glycosyl acceptor. This occurs in the constant domains of antibodies such as IgG.