Answer:
5.28g
Explanation:
The equation for the reaction between is given below:
HCl + NaOH —> NaCl + H2O
Let us determine which will be the limiting reactant.
Molar Mass of HCl = 1 + 35.5 = 36.5g/mol
Mass of HCl = 3.3g
Number of mole = Mass /Molar Mass
Number of mole of HCl = 3.3/36.5 = 0.09mole
Molar Mass of NaOH = 23 + 16 + 1 = 40g/mol
Mass of NaOH = 4.6g
Number of mole = Mass /Molar Mass
Number of mole of NaOH = 4.6/40 = 0.115mole
From the equation,
1mole of HCl required 1mole of NaOH.
Therefore, 0.09mole of HCl will also require 0.09mole of NaOH.
Now, we see that NaOH is excess and HCl is limiting.
Now we can calculate the theoretical yield as follows:
Molar Mass of NaCl = 23 + 35.5 = 58.5g/mol
From the equation,
36.5g of HCl produced 58.5g of NaCl.
Therefore, 3.3g of HCl will produce = (3.3 x 58.5)/36.5 = 5.28g
Therefore, the theoretical yield of NaCl is 5.28g