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Ronch [10]
3 years ago
7

Juan created a chart to help him study for a test.

Chemistry
2 answers:
Helga [31]3 years ago
4 0

Answer:

The Answer is B. X: Opaque Objects

      > > >               Y: Transparent Objects

Explanation:

dimulka [17.4K]3 years ago
3 0

Answer:

B) X: Opaque Objects

Y: Transparent Objects

Explanation:

Just had this question and got it right

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A student repeats a reaction several times to test the effects of various
klio [65]

Answer:

The correct answer is - C.  Increasing the concentration increases the reaction rate.

Explanation:

In the given question the data with change in different factors affect the rate of reaction differently as it alters the time it takes to complete reaction:

Conditions                            Reaction Time

Original                                  10 seconds

Higher concentration            5 seconds

Higher temperature              5 seconds  

Metal added                           5 seconds

As it is given above, time is decreased in each condition including in the case of increasing the concentration of the reactants which means the rate of reaction increases as well.

8 0
3 years ago
Consider the following reaction of calcium hydride (CaH2) with molten sodium metal: CaH2(s) 2 Na(l) -> 2 NaH(s) Ca(l) Identif
pashok25 [27]

Answer:

None of the species in the equation have undergone either oxidation or reduction

Explanation:

The easiest way to see if oxidation or reduction has happened is to compare oxidation numbers of each and every species before and after the reaction.

Calcium is two before the reaction and two after the reaction

Hydrogen is -1 before the reaction and -1 after the reaction

Sodium is one before the reaction and one after the reaction

Iodine is -1 before the reaction and -1 after the reaction.

For an oxidation to happen an increase in oxidation number has to happen.

For a reduction to happen, a decrease in oxidation number has to happen. None have happened

8 0
3 years ago
which statement regarding the relative energies of monochromatic light with with λ = 800 nm andmonochromatic light with λ = 400
olga2289 [7]

Answer:

The correct answer is option A.

Explanation:

Energy of the photon of an electromagnetic radiation is give by Planck's equation:

E=\frac{hc}{\lambda }

Where:

h = Planck's constant

c = speed of light

\lambda = Wavelength of the photon's radiation

Energy of photon of 800 nm monochromatic light

\lambda = 800 nm=400\times 10^{-9} m

E=\frac{hc}{800 \times 10^{-9} m}

Energy per mole of photons:

E\times N_A=\frac{hc}{800 \times 10^{-9} m}\times 6.022\times 10^{23} mol^{-1}..[1]

Energy of photon of 400 nm monochromatic light

\lambda '= 400 nm=400\times 10^{-9} m

Energy per mole of photons:

E'\times N_A=\frac{hc}{400 \times 10^{-9} m}\times 6.022\times 10^{23} mol^{-1}..[2]

[1] ÷ [2]

\frac{E\times N_A}{E'\times N_A}=\frac{\frac{hc\trimes 6.022\times 10^{23} mol^{-1}}{800 \times 10^{-9} m}}{\frac{hc\times 6.022\times 10^{23} mol^{-1}}{400 \times 10^{-9} m}}

\frac{E}{E'}=\frac{1}{2}

E=\frac{1}{2}\times E'

8 0
3 years ago
Read 2 more answers
15 points for only two question :) please help
vodomira [7]
Ionization energy increases as you move left to right in a period . that's why noble gases have high ionization energies.
shielding effect increases from top to bottom in a group atomic size also increases from top to bottom in a group
8 0
4 years ago
Write an equation that shows the formation of a copper (I) ion from a neutral copper atom
kumpel [21]
Cu ----> Cu(+) + 1 e-
5 0
3 years ago
Read 2 more answers
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