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Debora [2.8K]
3 years ago
5

If f(x) = x^2 - 4x + 1, find the range of f(x). {y: y ≥ -3} {y: y ≥ 13} all reals

Mathematics
1 answer:
Tomtit [17]3 years ago
8 0
Hello : 
y= <span>x² - 4x + 1
calculate : x 
y = (x²-4x+4)-4+1
y+3 = (x-2)²
x exist : if   y+3 </span><span>≥ 0
y </span><span>≥ -3
the range is : </span><span>{y: y ≥ -3}</span>
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To solve this problem, we have to manually solve for the value of x for each choices or equations. The correct equation will give a value of -1 since the linear equations intersects at point (-1, -4).

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7x – x = 3 – 3

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<span>x = 0                (FALSE)</span>

 

<span>2nd: 7x − 3 = x – 3</span>

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<span>3rd: 7x + 3 = x − 3</span>

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<span>4th: 7x − 3 = x + 3</span>

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Therefore the answer is:

<span>7x + 3 = x − 3</span>

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