Question

If f(x) = x^2 - 4x + 1, find the range of f(x). {y: y ≥ -3} {y: y ≥ 13} all reals

Answer 1

Hello : 
y= x² - 4x + 1
calculate : x 
y = (x²-4x+4)-4+1
y+3 = (x-2)²
x exist : if   y+3 ≥ 0
y ≥ -3
the range is : {y: y ≥ -3}