Answer:
-390 mph
Step-by-step explanation:
Let a and b represent, respectively, the distances of A and B from the airport. The distance d between the planes is then given by the Pythagorean theorem as ...
d² = a² + b²
Differentiating with respect to time, we have ...
2d·d' = 2a·a' +2b·b'
Solving for d', we get ...
d' = (a/d)a' +(b/d)b'
The value of d at the time of interest is ...
d = √(a² +b²) = √(30² +40²) = √2500 = 50
Then the rate of change of separation is ...
d' = (30/50)(-250 mph) +(40/50)(-300 mph) = (-150 -240) mph
d' = -390 mph
The distance between planes is decreasing at 390 miles per hour.
Answer:
No solutions: 7−5+3x−1= 3x + 7
One solution: 7−5+3x−1= 2x + 4
Infinitely Many Solutions 7−5+3x−1= 3x + 1
Step-by-step explanation:
No solutions means it results in no x and a false statement like 3 = 0.
One solution means it results in x = a number.
Infinite solutions means its results in no x and in a true statement like 3=3.
- So to get No solutions: 7−5+3x−1= 3x + 7
This will eliminate the x and result in 1 = 7 which is false.
- One solution: 7−5+3x−1= 2x + 4
This will result in x= 3
- Infinitely Many Solutions 7−5+3x−1= 3x + 1
This will eliminate the x and result in 1 = 1 which is true.
Answer:
Inter-quartile range
Step-by-step explanation:
When you have the quartile, you can use the IQR (interquartile range) to measure the dispersion.
IQR = Q3 - Q1
Movies: IQR = 195 - 162 = 33
Basketball: IQR = 225 - 170 = 55
Attendance at Basketball is more dispersed/spread out as compared to attendance at Movies
Answer:
Total area = 237.09 cm²
Step-by-step explanation:
Given question is incomplete; here is the complete question.
Field book of an agricultural land is given in the figure. It is divided into 4 plots. Plot I is a right triangle, plot II is an equilateral triangle, plot III is a rectangle and plot IV is a trapezium, Find the area of each plot and the total area of the field. ( use √3 =1.73)
From the figure attached,
Area of the right triangle I = 
Area of ΔADC = 
= 
= 
= 
= 
= 30 cm²
Area of equilateral triangle II = 
Area of equilateral triangle II = 
= 
= 73.0925
≈ 73.09 cm²
Area of rectangle III = Length × width
= CF × CD
= 7 × 5
= 35 cm²
Area of trapezium EFGH = 
Since, GH = GJ + JK + KH
17 = 
12 = 
144 = (81 - x²) + (225 - x²) + 2
144 - 306 = -2x² + 
-81 = -x² + 
(x² - 81)² = (81 - x²)(225 - x²)
x⁴ + 6561 - 162x² = 18225 - 306x² + x⁴
144x² - 11664 = 0
x² = 81
x = 9 cm
Now area of plot IV = 
= 99 cm²
Total Area of the land = 30 + 73.09 + 35 + 99
= 237.09 cm²
0.2642 gallons is your amazing answer<span />