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Kisachek [45]
3 years ago
7

Plz Help ASAP!!!! Which of the following statements demonstrates the associative property of multiplication? a. 4 ∙ (3 ∙ 6) = (4

∙ 3) ∙ 6 b. 6 ∙ 4 = 4 ∙ 6 c. -3 ∙ 1 = -3 d. 2(24) = 2(20 + 4)
Mathematics
2 answers:
777dan777 [17]3 years ago
6 0

Answer:

A is your answer

Step-by-step explanation:

marta [7]3 years ago
3 0

Answer:

The answer is A. 4 * (3 * 6) = (4 * 3) * 6

Step-by-step explanation:

In the associative property of multiplication, it states that the order of parentheses doesn't matter.

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How to find the vertex calculus 2What is the vertex, focus and directrix of x^2 = 6y
son4ous [18]

Solution:

Given:

x^2=6y

Part A:

The vertex of an up-down facing parabola of the form;

\begin{gathered} y=ax^2+bx+c \\ is \\ x_v=-\frac{b}{2a} \end{gathered}

Rewriting the equation given;

\begin{gathered} 6y=x^2 \\ y=\frac{1}{6}x^2 \\  \\ \text{Hence,} \\ a=\frac{1}{6} \\ b=0 \\ c=0 \\  \\ \text{Hence,} \\ x_v=-\frac{b}{2a} \\ x_v=-\frac{0}{2(\frac{1}{6})} \\ x_v=0 \\  \\ _{} \\ \text{Substituting the value of x into y,} \\ y=\frac{1}{6}x^2 \\ y_v=\frac{1}{6}(0^2) \\ y_v=0 \\  \\ \text{Hence, the vertex is;} \\ (x_v,y_v)=(h,k)=(0,0) \end{gathered}

Therefore, the vertex is (0,0)

Part B:

A parabola is the locus of points such that the distance to a point (the focus) equals the distance to a line (directrix)

Using the standard equation of a parabola;

\begin{gathered} 4p(y-k)=(x-h)^2 \\  \\ \text{Where;} \\ (h,k)\text{ is the vertex} \\ |p|\text{ is the focal length} \end{gathered}

Rewriting the equation in standard form,

\begin{gathered} x^2=6y \\ 6y=x^2 \\ 4(\frac{3}{2})(y-k)=(x-h)^2 \\ \text{putting (h,k)=(0,0)} \\ 4(\frac{3}{2})(y-0)=(x-0)^2 \\ Comparing\text{to the standard form;} \\ p=\frac{3}{2} \end{gathered}

Since the parabola is symmetric around the y-axis, the focus is a distance p from the center (0,0)

Hence,

\begin{gathered} Focus\text{ is;} \\ (0,0+p) \\ =(0,0+\frac{3}{2}) \\ =(0,\frac{3}{2}) \end{gathered}

Therefore, the focus is;

(0,\frac{3}{2})

Part C:

A parabola is the locus of points such that the distance to a point (the focus) equals the distance to a line (directrix)

Using the standard equation of a parabola;

\begin{gathered} 4p(y-k)=(x-h)^2 \\  \\ \text{Where;} \\ (h,k)\text{ is the vertex} \\ |p|\text{ is the focal length} \end{gathered}

Rewriting the equation in standard form,

\begin{gathered} x^2=6y \\ 6y=x^2 \\ 4(\frac{3}{2})(y-k)=(x-h)^2 \\ \text{putting (h,k)=(0,0)} \\ 4(\frac{3}{2})(y-0)=(x-0)^2 \\ Comparing\text{to the standard form;} \\ p=\frac{3}{2} \end{gathered}

Since the parabola is symmetric around the y-axis, the directrix is a line parallel to the x-axis at a distance p from the center (0,0).

Hence,

\begin{gathered} Directrix\text{ is;} \\ y=0-p \\ y=0-\frac{3}{2} \\ y=-\frac{3}{2} \end{gathered}

Therefore, the directrix is;

y=-\frac{3}{2}

3 0
1 year ago
What is the solution for 4x+5=
Mamont248 [21]
I think the answer is 9
4 0
3 years ago
Read 2 more answers
Hey can you please help me posted picture of question
GREYUIT [131]
To solve this problem you must apply the proccedure shown below:

 1. You have the following expression:

 (3+3i)-(13+15i)

 2. If you want to substract both terms, you  need to substract the real numbers and the complex numbers. Then, you obtain:

 3+3i-13-15i
 (3-13)+(3i-15i)

 3. Then, you obtain the following result:

 -10-12i

 4. Therefore, as you can see, the correct answer is the last option (option D), which is:
 D. -10-12i
4 0
3 years ago
The sum of m and 10
GREYUIT [131]

Answer:

  1. m + 10
  2. c - 24
  3. 8 + 12
  4. (3×7) - 5
  5. (7 + a) × 6
  6. y ÷ (-5)
  7. (x - y) ÷ 3
  8. {(a + b)}^{2}  \div 3c
3 0
3 years ago
PLEASE HELP 30 POINTS DONT HAVE TO SHOW WORK 3 ATTACHMENTS PLEASE ANSWER ALL
Eva8 [605]
First one answer is C.
log3(1/81) = -4

-------------
log(45) / log(2) = 5.4919

answer
A. 5.4919
--------------------
next step
x - 1 = 3x+9
2x - 10
x = -5

answer
D. x - 1 = 3x+9

4 0
3 years ago
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