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2 years ago

7

Plz Help ASAP!!!! Which of the following statements demonstrates the associative property of multiplication? a. 4 ∙ (3 ∙ 6) = (4

∙ 3) ∙ 6 b. 6 ∙ 4 = 4 ∙ 6 c. -3 ∙ 1 = -3 d. 2(24) = 2(20 + 4)

2 answers:

777dan777 [17]2 years ago

6 0

Answer:

A is your answer

Step-by-step explanation:

marta [7]2 years ago

3 0

Answer:

The answer is A. 4 * (3 * 6) = (4 * 3) * 6

Step-by-step explanation:

In the associative property of multiplication, it states that the order of parentheses doesn't matter.

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Fill in the blanks to complete the area model to solve 6.60 divided by 15 is the same as _ x ? = _ 6.60 = _ hundredths

storchak [24]

Answer:

$15 x = 6.60$

$x = 44\ hundredths$

Step-by-step explanation:

Given

$\frac{6.60}{15}$

Required

Complete the model

[ ] x = 6.60

x = _ hundredths

$\frac{6.60}{15}$

Equate to x

$x = \frac{6.60}{15}$

Multiply both sides by 15

$15 * x = \frac{6.60}{15} * 15$

$15 * x = 6.60$

$15 x = 6.60$

So, we have:

[ ] x = 6.60 =====> $15 x = 6.60$

Recall that:

$x = \frac{6.60}{15}$

$x = 0.44$

This implies that:

$x = 44\ hundredths$

Hence:

x = _ hundredths =====> $x = 44\ hundredths$

3 0

2 years ago

Please give answer for this

andrew-mc [135]

Answer:

100 square cm

Step-by-step explanation:

Area of figure 1 = l *b = 10 *7 = 70 square cm

Area of figure 2 = 6* 5 = 30 square cm

Area of shape = 70 + 30 = 100 square cm

6 0

2 years ago

HElp me please!!! IVE HAD TROUBLE W THIS SINCE 11

Neporo4naja [7]

Answer:

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Step-by-step explanation:

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3 years ago

If log2 5 = k, determine an expression for log32 5 in terms of k.

lukranit [14]

Answer:

$log_3_2(5)=\frac{1}{5} k$

Step-by-step explanation:

Let's start by using change of base property:

$log_b(x)=\frac{log_a(x)}{log_a(b)}$

So, for $log_2(5)$

$log_2(5)=k=\frac{log(5)}{log(2)}\hspace{10}(1)$

Now, using change of base for $log_3_2(5)$

$log_3_2(5)=\frac{log(5)}{log(32)}$

You can express $32$ as:

$2^5$

Using reduction of power property:

$log_z(x^y)=ylog_z(x)$

$log(32)=log(2^5)=5log(2)$

Therefore:

$log_3_2(5)=\frac{log(5)}{5*log(2)}=\frac{1}{5} \frac{log(5)}{log(2)}\hspace{10}(2)$

As you can see the only difference between (1) and (2) is the coefficient $\frac{1}{5}$ :

So:

$\frac{log(5)}{log(2)} =k\\$

$log_3_2(5)=\frac{1}{5} \frac{log(5)}{log(2)} =\frac{1}{5} k$

6 0

2 years ago

530 divided by 16 give the quotient and remainder

damaskus [11]

33
_____
16 | 530
48
-------
50
48
----------
2

quotient = 33
remainder = 2

6 0

2 years ago