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Artist 52 [7]
3 years ago
12

What is the slope of a line parallel to the line whose equation is x+2y=2

Mathematics
1 answer:
dmitriy555 [2]3 years ago
7 0

Step-by-step explanation:

Parallel lines have the same slope.

x + 2y = 2 \\ 2y = x - 2 \\ y = 0.5x - 1

y = mx + b \\ m \: is \: the \: slope \: so \: te \: slope \: is \:  \frac{1}{2}

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80% or 4/5
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15 - 5 x = 10 x + 45
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Answer:

x=-2

Step-by-step explanation:

add 5x , then subtract 45, then divide by 15

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Anne runs 6 laps on a track. She runs a total of 1 mile or 5,280 feet. Write and solve an equation to find the distance, in feet
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What is the radius of the base of the cylinder 42in and 36 in
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Need additional information, which is the height and which is the diameter of the cylinder from the measurements supplied?  Standard forumula for locating Radius and Volume of a cylinder are as follows.

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8 0
3 years ago
Media experts claim that daily print newspapers are declining because of Internet access. Listed​ below, from left to right and
yKpoI14uk [10]

Answer:

(a) The median is 1478

(b) Null hypothesis H₀ : μ₁ = μ₂

Alternative hypothesis Hₐ : μ₁ > μ₂

(c) The test statistic  t_{\alpha/2} is 6.678155

(d) The p value is  1.2×10⁻¹¹

(e) We reject our null hypothesis H₀. In terms of the test, there is sufficient evidence to suggest that there is a trend in the numbers of daily newspaper because the probability for a decrease in the numbers is very high

Step-by-step explanation:

(a) Here we have the data as follows;

1623 1586 1574 1554 1544 1531 1519 1513 1491 1484 1478 1471 1458 1456 1458 1453 1438 1428 1405 1395 1377

The median is = 1478

Therefore we have above the median  

1623 1586 1574 1554 1544 1531 1519 1513 1491 1484

The mean,  \bar{x}_{1}= 1541.9

Standard deviation, σ₁ = 41.38224257

n₁ = 10

Below the median  

1471 1458 1456 1458 1453 1438 1428 1405 1395 1377

The mean,  \bar{x}_{2}}= 1433.9

Standard deviation, σ₂ = 30.04812806

n₂ = 10

(b) Null hypothesis H₀ : μ₁ = μ₂

Alternative hypothesis Hₐ : μ₁ > μ₂

(c) The formula for t test is given by;

t_{\alpha/2} =\frac{(\bar{x}_{1}-\bar{x}_{2})}{\sqrt{\frac{\sigma_{1}^{2} }{n_{1}}-\frac{\sigma _{2}^{2}}{n_{2}}}}

df = 10 - 1 = 9, α = 0.05

Therefore, the test statistic  t_{\alpha/2} = 6.678155

(d) The p value from statistical relations is Probability p = 1.2×10⁻¹¹

Critical z at 5% confidence level = 1.645

Since P << 0.05, e reject the

(e) Therefore, we reject our null hypothesis H₀. In terms of the test, there is sufficient evidence to suggest that there is a trend in the numbers of daily newspaper because the probability for a decrease in the numbers is very high.

5 0
3 years ago
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