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nexus9112 [7]
4 years ago
8

4b×3b-2b=102 what is b

Mathematics
2 answers:
jeka944 years ago
7 0
4b×3b-2b=102
12b^2 - 2b = 102
12b^2 - 2b - 102 = 0
divide by 2
6b^2 - b - 51
(6b + 17)(b - 3) = 0
6b + 17 = 0
6b = -17
b = -17/6 or 2 5/6
b - 3 = 0
b = 3
Over [174]4 years ago
7 0
4b\cdot3b-2b=102\\
12b^2-2b-102=0\\
6b^2-b-51=0\\
6b^2+17b-18b-51=0\\
b(6b+17)-3(6b+17)=0\\
(b-3)(6b+17)=0\\\
b=3 \vee b=-\frac{17}{6}
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Can someone help me please!!
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When we factor out the GCF of -3, we get:
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Next, we must look for two numbers that will serve as coefficients for the variables in factored form.  These two numbers must add to 7 (the middle term) and multiply to 10 (the constant or last term).  The two numbers that satisfy these parameters are 5 and 2.

Therefore, we must use these numbers to create factors of the innermost factor that we have left, to get:

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Answer:

Step-by-step explanation:

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