URGENT! What is the value of x?

The side lengths, in centimeters, of a triangle are 5x, 32, and 2(3x + 2). perimeter of the triangle is 80 centimeters. what is

Lerok [7]

Answer:

20 cm

Step-by-step explanation:

5x + 32 + 6x + 4 = 80

11x + 36 = 80

11x = 44

x = 4

sides of triangle:

5(4) = 20 cm

32 cm

6(4) + 2 = 26 cm

4 0

2 years ago

How do you divide 4 sandwiches between 6 people equally

Luba_88 [7]

Slice each sandwich in half then the remainder is 2 for u!

7 0

2 years ago

tire and Jody's bedroom are shaped like rectangles Terrace bedroom is 9 ft long and 8 feet wide Jody's bedroom is 7 ft long and

zloy xaker [14]

Terrace, because area= length (l) * width (w). Since terrace's room is 9 by 8, you multiply 9*8 which gives you 72ft squared. Jody's bedroom id 7*10 which gives you 70 ft squared. 72 is greater than 70.

3 0

3 years ago

Solve Please. No Links. Links = Report.

AfilCa [17]

Answer:

Step-by-step explanation:

The easiest way to start is to do this problem is to start changing the 3/4 cup to a decimal

3/4 = 0.75

Now divide that into 11. What you are interested in is the remainder.

11/0.75 = 14.66667

He can make 14 whole pizzas.

He has 0.66667 of a cup left over which is less than 3/4 (or 0.75) so he does not have enough for another pizza.

So the answer is 0.66667 which is 2/3 of a cup is left over.

7 0

2 years ago

Use undetermined coefficient to determine the solution of:y"-3y'+2y=2x+ex+2xex+4e3x

Kitty [74]

First check the characteristic solution: the characteristic equation for this DE is

r ² - 3r + 2 = (r - 2) (r - 1) = 0

with roots r = 2 and r = 1, so the characteristic solution is

y (char.) = C₁ exp(2x) + C₂ exp(x)

For the ansatz particular solution, we might first try

y (part.) = (ax + b) + (cx + d) exp(x) + e exp(3x)

where ax + b corresponds to the 2x term on the right side, (cx + d) exp(x) corresponds to (1 + 2x) exp(x), and e exp(3x) corresponds to 4 exp(3x).

However, exp(x) is already accounted for in the characteristic solution, we multiply the second group by x :

y (part.) = (ax + b) + (cx ² + dx) exp(x) + e exp(3x)

Now take the derivatives of y (part.), substitute them into the DE, and solve for the coefficients.

y' (part.) = a + (2cx + d) exp(x) + (cx ² + dx) exp(x) + 3e exp(3x)

… = a + (cx ² + (2c + d)x + d) exp(x) + 3e exp(3x)

y'' (part.) = (2cx + 2c + d) exp(x) + (cx ² + (2c + d)x + d) exp(x) + 9e exp(3x)

… = (cx ² + (4c + d)x + 2c + 2d) exp(x) + 9e exp(3x)

Substituting every relevant expression and simplifying reduces the equation to

(cx ² + (4c + d)x + 2c + 2d) exp(x) + 9e exp(3x)

… - 3 [a + (cx ² + (2c + d)x + d) exp(x) + 3e exp(3x)]

… +2 [(ax + b) + (cx ² + dx) exp(x) + e exp(3x)]

= 2x + (1 + 2x) exp(x) + 4 exp(3x)

… … …

2ax - 3a + 2b + (-2cx + 2c - d) exp(x) + 2e exp(3x)

= 2x + (1 + 2x) exp(x) + 4 exp(3x)

Then, equating coefficients of corresponding terms on both sides, we have the system of equations,

x : 2a = 2

1 : -3a + 2b = 0

exp(x) : 2c - d = 1

x exp(x) : -2c = 2

exp(3x) : 2e = 4

Solving the system gives

a = 1, b = 3/2, c = -1, d = -3, e = 2

Then the general solution to the DE is

y(x) = C₁ exp(2x) + C₂ exp(x) + x + 3/2 - (x ² + 3x) exp(x) + 2 exp(3x)

4 0

2 years ago