Answer:
10
Step-by-step explanation:
In this system of equations, I'll do elimination. Ok, so what we are trying to do is to eliminate a variable, but we can't. So since -2y is negative, and y has a coefficient of 1 and is positive, let's multiply the first whole equation by 2.
2 times (3x+y=11) is 6x+2y=22. (I just used distributive property.) Now let's add from left to right.
6x plus x is 7x, 2y plus -2y is 0, and 22 plus 6 is 28. Now we have this simple equation, 7x=28. We can simply divide each side by 7, to get x as 4. So x=4 in this set of equations. Now all we need to do is plug x in the equation then solve for y. For this system of equations, I'll use the first equation, because it is easier. So I'll plug x as 4 into the equation to get 12+y=11. Now we can simply solve for y. 11-12 is -1, so y must equal -1. So y=-1. Therefore, x=4 and y=-1. Hope I helped.
Answer:
B. The interquartile range is 55
Step-by-step explanation:
the interquartile range is Q3 minus Q1, you would get 15 ,not 55. So B is the answer to your question
Step-by-step explanation:
15t + 30 = 20t | -15t
30 = 5t
t = 30/5 = 6
20 + 5t = -6t + 86 | + 6t
20 + 11t = 86 | -20
11t = 66
t = 6
18t + 20 = 24t + 50 | -18t
20 = 6t + 50 | -50
-30 = 6t
t = -30/6 = -5
18t - 2 = 10t + 54 | -10t
8t - 2 = 54 | +2
8t = 56
t = 56/8 = 7
7t - 5 = 15t + 91 | -7t
-5 = 8t + 91 | -91
-96 = 8t
t = -96/8 = -12
