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Anuta_ua [19.1K]
3 years ago
6

First one how you do it and the second one is the problem

Mathematics
1 answer:
MrRissso [65]3 years ago
4 0
You didn’t upload any picture maybe you forgot to
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-7 x - 2y = -13 <br> x - 2y = 11
VashaNatasha [74]
Well the first one would convert to
-2y= 7x-13 and the second one would be -2y=-x+11 and you solve from there (lmk if you need the steps) but your final answer would be. Y= -7/2x+ 13/2 and y=1/2x - 11/2
8 0
3 years ago
The ratio of the leg opposite to an angle to the leg adjacent to the angle in a right
enot [183]
Sine is opposite over adjacent
5 0
3 years ago
Read 2 more answers
Given circle E with diameter CD and radius EA. AB is tangent to Eat A.
faust18 [17]

The hypotenuse is equal to the square of the other two sides. The length of AC from the diagram is 21.9feet

<h3>Application of pythagoras theorem</h3>

The theorem states that the square of the hypotenuse is equal to the square of the other two sides

Given the following

Hypotenuse = 26 feet = CD
Base side = AD = 14ft

Required

Length AC

Use the theorem

26^2 = 14^2 + AC^2

AC^2 =  676 - 196
AC^2 = 480
AC = 21.9feet

Hence the length of AC from the diagram is 21.9feet

Learn more on pythagoras theorem here: brainly.com/question/343682

8 0
2 years ago
HURRY! 1. The Junior Garden Club has $144 for their special project which is the planting of a flower garden near the high schoo
Ber [7]
For 144$ u can buy 36 rose stands and that’s it. Or with the 144$ u could buy 20 tulips
5 0
3 years ago
The Palue of the digit in the hundredths place is
Harman [31]

Answer:The value of the digit in the hundredths place is 10 times as great as the value of the digit in the tenths place.

Explained: The model shows that your number is 0.11

We have to find what we can multiply to become the 1 in the tenths place. Since they are the same number but in different places, we just multiply it by 10 to change the value.

So, if you multiply 10 by the 1 in the hundredths place, it will get you to the 1 in the tenths place.

♡<em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em><em>♡</em>

7 0
3 years ago
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