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3 years ago

Help please ...a square card has an area of 15 in.^2 what is the approximate side length of the card

2 answers:

6 0

Area = side length²
Because it's a square, all of the side lengths are equal.
15 = s²
s = √(15)
s = √(15) inches

Hope this helps!

kap26 [50]3 years ago

6 0

$x-the\ length\ of\ the\ side\ a\ square\ card\\\\A_{\fbox{}}=x^2;\ A_{\fbox{}}=15\ in^2\\\\therefore:x^2=15\ in^2\\\\x=\sqrt{15}\ in\\\\\boxed{x\approx3.87\ in}$

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If A = {4, 7, 10, 13, 17} and B = {3, 5, 7, 9}, then which of the following statements is true?

Marysya12 [62]

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3 years ago

What is the greatest common factor of 10, 20, and 50?

Viefleur [7K]

Answer:

Step-by-step explanation:

first you need to find the prime factors of the three numbers

ex:

prime factor of 18= $2*3*3$

prime of 24= $2*2*2*3$

there is one 2 and one 3 in common

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so the greatest common multiple is ten because it is the only one that can divide between all three evenly.

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3 years ago

what is the answer to the volleyball team at blue point high school has saved $680 and the team plans to spend no more then that

zloy xaker [14]

Answer:

6 x + 23 y < $ 680 represents the combinations of x balls and y nets that can be purchased.

Step-by-step explanation:

The number of balls than can be purchased = x

The number of nets than can be purchased = y

Total savings = $ 680

Now, the cost of 1 ball =$6

So, the cost of x balls = x ( cost of 1 ball) = x ( $6) = 6 x

Also, the cost of 1 net =$23

So, the cost of y nets = y ( cost of 1 net = y ( $23) = 23 y

So, the total amount spent on x balls and y nets

= Amount spent on x balls + Amount on y nets

= 6 x + 23 y

Also, the saved amount is $680

⇒<u> 6 x + 23 y < $ 680</u>

Hence, 6 x + 23 y < $ 680 represents the combinations of x balls and y nets that can be purchased.

4 0

3 years ago

Please help this is 8th grade math

topjm [15]

Answer:

Step-by-step explanation:

The point starts at 250 on the Y-Axis

5 0

3 years ago

Read 2 more answers

48x^2 +44x=60 which of the following could be used to find the solution to the equation above? Select all that apply

levacccp [35]

Because the polynomial has degree 2, we can assume that there are 2 solutions (roots), whether real or imaginary.

You can subtract 60 in order to put this in standard form

48x^2+44x-60 = 0

From there, just put a,b, and c into the quadratic formula and you're good to solve for your answers.

(-b+-sqrt(b^2-4ac))/2a

(-44+-sqrt(44^2-4(48)(-60)))/2(48)

Then solve.

There is probably a better way, but this should give you the two roots/solutions.

8 0

3 years ago