Can anyone help with this?
1 answer:
Find the area of all three of them then add them together.
TRIANGLE:
A=1/2*b*h
A=1/2*8*h
The height is not given to us, so we need to make a separate triangle to figure it out. (Work is in picture 1)
A=1/2*8*6.9
A=27.7
SQUARE:
A=s^2
A=8^2
A=64
POLYGON:
Area=1/2*a*p
The polygon has 5 sides.
The perimeter will be 8*5, or 40.
The apothem is found in the next snapshot.
A=1/2*1.9*40
A=38
TOTAL AREA:
38+22.7+64=124.7
TRIANGLE:
A=1/2*b*h
A=1/2*8*h
The height is not given to us, so we need to make a separate triangle to figure it out. (Work is in picture 1)
A=1/2*8*6.9
A=27.7
SQUARE:
A=s^2
A=8^2
A=64
POLYGON:
Area=1/2*a*p
The polygon has 5 sides.
The perimeter will be 8*5, or 40.
The apothem is found in the next snapshot.
A=1/2*1.9*40
A=38
TOTAL AREA:
38+22.7+64=124.7
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Answer:
x=-3,y=-2
Step-by-step explanation:
Given 2 expressions
S1:
S2:
Write one equation in terms of any variable (x or y)
Here I am writing S1 in terms of y
Substitute this value of y as the value of y in S2
⇒
Therefore
Substitute this value of x in any of the expressions S1 or S2
Here i am substituting in S2
⇒
Therefore x=-3 and y=-2