Question

A basketball-player scores a free-throw with probability 0.9. What is the probability that her first miss occurs on the 6th shot

Answer 1

Answer:

$Pr = 0.059049$

Step-by-step explanation:

Given

$p = 0.9$ --- probability of scoring

Required

Probability that his first miss is his 6th shot

Let q represent the event that he did not score.

Using complement rule:

$q = 1 - p = 1 - 0.9 = 0.1$

The event that his first miss is his 6th is represented as:

p p p p p q ---- That he scoress the first 5 attempts

So, the probability is:

$Pr = p^5 * q$

$Pr = 0.9^5 * 0.1$

$Pr = 0.059049$