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DochEvi [55]
3 years ago
14

Please answer it will mark brilliantnest​

Mathematics
1 answer:
nikdorinn [45]3 years ago
4 0
13,14,15
Plz mark me as the brilliantnest
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KG passes through the point (2, 14) and intersects HG at the point (12, 4). If the point H(18, 10) lies on HG, write the equatio
Setler79 [48]
The equation for KG would be y-14=-1(x-2) and the equation for HG would be y-4=1(x-12).

We first find the slope of KG.  The formula for slope is
m=(y₂-y₁)/(x₂-x₁)

Using the points we have for KG, we have
m=(4-14)/(12-2) = -10/10 = -1

The equation for point-slope form is
y-y₁=m(x-x₁)

Using the slope of KG and the first point listed for that line, we have
y-14=-1(x-2)

Now we find the slope of HG:
m=(10-4)/(18-12) = 6/6 = 1

Using the point of intersection for KG and HG, we have
y-4=1(x-12)
3 0
3 years ago
(4 + 2n) + (513 + 2).
yulyashka [42]

Answer:

2n + 519

Step-by-step explanation:

Hope this helps! :)

Good luck♥

8 0
3 years ago
Solve this questions:​
In-s [12.5K]
1 x=1/3 2 x =3/2 y =3/2
8 0
3 years ago
A sequence is defined recursively using the formula f(n + 1) = –0.5 f(n) . If the first term of the sequence is 120, what is f(5
Svetllana [295]
7.5
f(1) = 120
f(2) = -60
f(3) = 30
f(4) = -15
f(5) = 7.5
6 0
4 years ago
Read 2 more answers
A card has p meters of lace edging wound on it. Nerys buys n lengths of edging, each x cm long. If Q meters of edging are left o
Diano4ka-milaya [45]

Answer:

Q = P - n(x/100)

Step-by-step explanation:

P is the total number of lace edging, n is the number of times the length x is cut from P, and Q is the remnant of the reduction.

So the number of x length is subtracted from P and must be converted to meters (since it is in centimeters) to get Q. That is;

Q = P - n(x/100)

5 0
3 years ago
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