Which decimal below best represents an account balance of $290.64 below zero?

A car can travel 396 miles on 22 gallons of gasoline.how much gasoline will it need to go 468 miles?

STatiana [176]

Answer:

396 miles / 22 gallons = 18 miles per gallon

468 miles / 18 miles = 26 gallons of gasoline

What I did is I took the number of miles and divided it by the number of gallons to find how many gallons of gasoline were used per mile. Then I took that number of miles and divided 468 by it because that's the number of gallons we are trying to find. We ended up with 26 gallons of gasoline for 468 miles.

7 0

3 years ago

Read 2 more answers

carmen y catalina comparan la nota que obtuvieron en su examen de nivelacion matematica y mencionan lo siguiente: nuestras notas

Rudiy27

Answer:

38?

Step-by-step explanation:

7 0

3 years ago

Greta answered 32 out of 40 questions correctly on a spelling test. what percentage of the words did she answer incorrectly?

vazorg [7]

Answer:

20%

Step-by-step explanation:

If you divide 32 out of 40, you will get .8. Multiply that by 100 and you will get 80%. The question asks for the percentage of incorrect ones, so subtract 80 out of 100 and you will get 20%.

She got 20% of the words incorrect.

5 0

3 years ago

Which of the following is an odd function?

Archy [21]

Option 4

f(x) = -x is an odd function

Solution:

A function is odd if and only if f(–x) = –f(x)

Option 1

$f(x) = x^3 + 5x^2 + x$

Substitute x = -x in above equation

$f(-x) = (-x)^3 + 5(-x)^2 + (-x)$

Cubes always involve multiplying a number by itself three times, so if the number is negative the cube will always be negative

Ans squaring results in positive

$f(-x) = -x^3 + 5x -x$ --- eqn 1

$-f(x) = -(x^3 + 5x^2 + x)\\\\-f(x) = -x^3 - 5x^2 - x$ ---- eqn 2

Comparing eqn 1 and eqn 2,

$f(-x) \neq -f(x)$

Therefore not an odd function

Option 2

$f(x) = \sqrt{x}$

$f(-x) = \sqrt{-x}$

$-f(x) = - \sqrt{x}$

Therefore,

$f(-x) \neq -f(x)$

Therefore not an odd function

Option 3

$f(x) = x^2 + x\\\\f(-x) = (-x)^2 + (-x)\\\\f(-x) = x^2 - x$

$-f(x) = -(x^2 + x) = -x^2 - x$

$f(-x) \neq -f(x)$

Therefore not an odd function

Option 4

$f(x) = -x\\\\f(-x) = -(-x) = x$

$-f(x) = -(-x) = x$

$f(-x) = -f(x)$

Thus option 4 is correct and it is an odd function

6 0

3 years ago

Find the x-intercepts of the parabola with

tia_tia [17]

Answer:

$(\frac{1}{2},0),(\frac{3}{2},0)$

Step-by-step explanation:

The vertex form of a parabola is given by:

$y=a(x-h)^2+k$ , where V(h,k) is the vertex of the parabola.

The given parabola has vertex (1,1).

This implies that: $h=1,k=1$ .

Put these values into the vertex form equation.

$\implies y=a(x-1)^2+1$

The y-intercept of this parabola is: (0,-3).

This point lies on the parabola hence it must satisfy its equation.

$\implies -3=a(0-1)^2+1$

$\implies -3=a(-1)^2+1$

$\implies -3=a(1)+1$

$\implies -3=a+1$

$\implies -3-1=a$

$\implies -4=a$

The equation now becomes

$\implies y=-4(x-1)^2+1$

To find the x-intercept, put y=0 into the equation:

$\implies -4(x-1)^2+1=0$

$\implies -4(x-1)^2=-1$

Divide through by -4.

$\implies \frac{-4(x-1)^2}{-4}=\frac{-1}{-4}$

$\implies (x-1)^2=\frac{-1}{-4}$

$\implies (x-1)^2=\frac{1}{4}$

Take plus or minus square root of both sides.

$\implies x-1=\pm \sqrt{\frac{1}{4}}$

$\implies x-1=\pm \frac{1}{2}$

$\implies x=1\pm \frac{1}{2}$

$\implies x=1-\frac{1}{2}$ or $\implies x=1+ \frac{1}{2}$

$\implies x=\frac{1}{2}$ or $\implies x=1 \frac{1}{2}$

Therefore the x-intercepts are:

$(\frac{1}{2},0),(\frac{3}{2},0)$

To the nearest hundredth, we have $0.50,0),(1.50,0)$

7 0

3 years ago