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sergiy2304 [10]
2 years ago
11

Find the missing length indicated

Mathematics
2 answers:
faltersainse [42]2 years ago
6 0

Answer:

D) 20

Step-by-step explanation:

Len [333]2 years ago
4 0

Answer:

D) 20

Step-by-step explanation:

they are asking for the longest length of the triangle. as you can see, 20 is just over 15, and from the diagram, the missing length is just over 15 so we can apply our knowledge to come to the answer of 20.

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Can someone help me and do it step by step
Tema [17]

Answer:

4

Step-by-step explanation:

65-25=40

40/10=4

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3 years ago
How many different passwords can be made if it is three letters, followed by two digits, followed by a letter?
ohaa [14]

Infinitely many passwords can be made.

8 0
2 years ago
Lenore is going to sell T-shirts at a field hockeygame to raise money for the team. She findsa website that makes custom T-shirt
sertanlavr [38]
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2 years ago
Sara is 9 years younger than her brother, Michael. The sum of their ages is 47 years. How old is Sara and how old is her brother
kotykmax [81]

Answer:

Michael is 38 and Sara is 29

Step-by-step explanation:

Because it says the sum of their age is 47 you do 47-9=38 so that would be Michael's age and than because Sara is 9 years younger than him and then you would do 38-9=29

7 0
2 years ago
In a football or soccer game, you have 22 players, from both teams, in the field. what is the probability of having at least any
Tamiku [17]

We can solve this problem using complementary events. Two events are said to be complementary if one negates the other, i.e. E and F are complementary if

E \cap F = \emptyset,\quad E \cup F = \Omega

where \Omega is the whole sample space.

This implies that

P(E) + P(F) = P(\Omega)=1 \implies P(E) = 1-P(F)

So, let's compute the probability that all 22 footballer were born on different days.

The first footballer can be born on any day, since we have no restrictions so far. Since we're using numbers from 1 to 365 to represent days, let's say that the first footballer was born on the day d_1.

The second footballer can be born on any other day, so he has 364 possible birthdays:

d_2 \in \{1,2,3,\ldots 365\} \setminus \{d_1\}

the probability for the first two footballers to be born on two different days is thus

1 \cdot \dfrac{364}{365} = \dfrac{364}{365}

Similarly, the third footballer can be born on any day, except d_1 and d_2:

d_3 \in \{1,2,3,\ldots 365\} \setminus \{d_1,d_2\}

so, the probability for the first three footballers to be born on three different days is

1 \cdot \dfrac{364}{365} \cdot \dfrac{363}{365}

And so on. With each new footballer we include, we have less and less options out of the 365 days, since more and more days will be already occupied by another footballer, and we can't have two players born on the same day.

The probability of all 22 footballers being born on 22 different days is thus

\dfrac{364\cdot 363 \cdot \ldots \cdot (365-21)}{365^{21}}

So, the probability that at least two footballers are born on the same day is

1-\dfrac{364\cdot 363 \cdot \ldots \cdot (365-21)}{365^{21}}

since the two events are complementary.

8 0
3 years ago
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