1. Angles ADC and CDB are supplementary, thus
m∠ADC+m∠CDB=180°.
Since m∠ADC=115°, you have that m∠CDB=180°-115°=65°.
2. Triangle BCD is isosceles triangle, because it has two congruent sides CB and CD. The base of this triangle is segment BD. Angles that are adjacent to the base of isosceles triangle are congruent, then
m∠CDB=m∠CBD=65°.
The sum of the measures of interior angles of triangle is 180°, therefore,
m∠CDB+m∠CBD+m∠BCD=180° and
m∠BCD=180°-65°-65°=50°.
3. Triangle ABC is isosceles, with base BC. Then
m∠ABC=m∠ACB.
From the previous you have that m∠ABC=65° (angle ABC is exactly angle CBD). So
m∠ACB=65°.
4. Angles BCD and DCA together form angle ACB. This gives you
m∠ACB=m∠ACD+m∠BCD,
m∠ACD=65°-50°=15°.
Answer: 15°.
Answer:
-8 and 6
Step-by-step explanation:
he spent 8 on the book, therefore he had deduced 8 dollars, and earned 6, therefore he had increased 6 dollars
Y = -7/4x + 19
You can get this by noting that at x = 12 of your new equation, y must equal -2 since it does presently on the y axis and you'll be shifting 12. So, you now have an ordered pair and the slope must stay the same. Then you can solve for the new y intercept by plugging in and solving for it.
Answer: The first one is17power-9
The second one is 1
Step-by-step explanation:
