So the equation is n/4-4=14
then you +4 to both sides
n/4-4=14 so now the equation is n/4=18 then you multiply 18 by 4 and get 72
+4 +4
then to check your work
72/4-4=14
so N=72
Hope I helped :)
Answer:
x = 6
Step-by-step explanation:
<em>If </em><em>two secants</em><em> are drawn from</em><em> a point outside </em><em>the circle, then the </em><em>product</em><em> of the lengths of</em><em> one secant </em><em>and its</em><em> external segment</em><em> equals the </em><em>product </em><em>of the lengths of</em><em> the other secant </em><em>and its</em><em> external segment</em><em> </em>
Let us solve the question.
∵ There is a circle in the given figure
∵ There are two secants intersected at a point outside the circle
∵ The length of one of them = 8
∵ The length of its external segment = x
∵ The length of the other secant = 4 + 8 = 12
∵ The length of its external segment = 4
→ By using the rule above
∴ 8 × x = 12 × 4
∴ 8x = 48
→ Divide both sides by 8
∴ x = 6
Answer:
There is no direct relation.
Step-by-step explanation:
8/6 = 4/3
16/8= 2/1
32/24= 4/3
If this were directly related, all of these would simplify to the same thing.
A - 2x^2 + 2x - 2
To find this, set up the equation:
(-x^2 + 6x - 1) + ( 3x^2 - 4x - 1)
With this, you need to combine like terms while taking into consideration the addition sign.
-x^2 + 3x^2 = 2x^2
6x + - 4x = 2x
- 1 + - 1 = - 2
Hope this helps!
