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mash [69]
3 years ago
13

Put together, Dulcina and Tremaine have 129 total matchbooks. Tremaine's collection has 39 fewer matchbooks in it than Dulcina's

collection. How many matchbooks are in Tremaine's collection? How many matchbooks are in Dulcina's collection?
Mathematics
1 answer:
Anit [1.1K]3 years ago
7 0

Answer:

Let the Dulcina's collection be 'x'

Let the Tremaine collection be 'x-39'

x + x - 39 =129

2x = 129 +39

2x = 168

x = 168/2

x = 84

Dulcina's collection = x = 84

Tremaine's collection = x - 39 = 84 - 39 = 45

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Anvisha [2.4K]

Answer:

<h3>Median = 6</h3><h3>Mean = 6,1</h3><h3>Modus = 7</h3>

Step-by-step explanation:

Median (Nila tengah setelah data diurutkan)

= 4, 4, 5, 5, 6, 6, 7, 7, 7, 8, 9

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Mean

= jumlah data / banyak data

= 4+4+5+5+6+6+7+7+7+8+9/11

= 68/11

= 6,1

Modus

= data yang paling banyak muncul

= 7 (muncul sebanyak 3 kali)

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how many such tests would it take for the probability of committing at least one type i error to be at least 0.7? (round your an
drek231 [11]

The number of tests that it would take for the probability of committing at least one type I error to be at least 0.7 is 118   .

In the question ,

it is given that ,

the probability of committing at least , type I error is = 0.7

we  have to find the number of tests ,

let the number of test be n ,

the above mentioned situation can be written as

1 - P(no type I error is committed) ≥ P(at least type I error is committed)

which is written as ,

1 - (1 - 0.01)ⁿ ≥ 0.7

-(0.99)ⁿ ≥ 0.7 - 1

(0.99)ⁿ ≤ 0.3

On further simplification ,

we get ,

n ≈ 118 .

Therefore , the number of tests are 118 .

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1 year ago
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Helga [31]

i think its f it just seems to be the most reasonable awnser a and i dont know this stuff :P

Step-by-step explanation:

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