Area of each piece of paper is 
Greatest number of possible piece of paper is![[1000\div\frac{187}{2}]=[1000\times\frac{2}{187}]=[\frac{2000}{187}]=10](https://tex.z-dn.net/?f=%5B1000%5Cdiv%5Cfrac%7B187%7D%7B2%7D%5D%3D%5B1000%5Ctimes%5Cfrac%7B2%7D%7B187%7D%5D%3D%5B%5Cfrac%7B2000%7D%7B187%7D%5D%3D10)
Greatest number of possible piece of paper is
Rewrite the equation in Ax+By=C form use integers for A.B. and C Y+3=6(x-1)
1 answer:
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<h3>Answer: Choice C</h3>
Started in Quadrant II and ended in Quadrant IV.
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Explanation:
Refer to the diagram below. It shows how the four quadrants are labeled using roman numerals. We start in the upper right corner (aka northeast corner) and work counterclockwise when labeling quadrant I, II, III, and IV in that order.
The green point A is located in quadrant II in the northwest. Meanwhile point B in red is in the southeast quadrant IV.
Therefore, we started in <u>quadrant II</u> and ended in <u>quadrant IV</u> which points us to <u>choice C.</u>