Answer:
Step-by-step explanation:
Area of rectangle = length * width
= (x + 4) (5x)
= x *5x + 4 *5x
= 5x² + 20x
Perimeter of rectangle = 2*(length + width)
= 2*(x + 4 + 5x)
= 2*(6x + 4)
= 2*6x + 2 *4
= 12x + 8
Answer:
m= 1/4
Step-by-step explanation:
tried helping I don't know if this is the right way to do it for you
Answer:
1/21
Step-by-step explanation:
Cards: 2,3,4,5,6,7,8 7 cards
1st card :5
P(5) = number of 5's / total
= 1/7
Then we keep the card
Cards: 2,3,4,6,7,8 only 6 cards left
card less than 4: 2,3
P (card less than 4) = number of cards less than 4/ total cards
= 2/6 = 1/3
P (5, no replacement, card less than 4) = P(5) * P( less than 4)
= 1/7 * 1/3
=1/21
Answer:
7
Step-by-step explanation:
To solve this, we have to work backwards. If you divide something by 9, and it equals 5, to figure out the number, we need to multiply by 9. 5*9= 45. If four was taken away, we have to add it to 45, which is 49. If a number *7 is 49, then we have to divide by 7 to get the answer. 49/7=7
Answer:
Yes, an arrow can be drawn from 10.3 so the relation is a function.
Step-by-step explanation:
Assuming the diagram on the left is the domain(the inputs) and the diagram on the right is the range(the outputs), yes, an arrow can be drawn from 10.3 and the relation will be a function.
The only time something isn't a function is if two different outputs had the same input. However, it's okay for two different inputs to have the same output.
In this problem, 10.3 is an input. If you drew an arrow from 10.3 to one of the values on the right, 10.3 would end up sharing an output with another input. This is allowed, and the relation would be classified as a function.
However, if you drew multiple arrows from 10.3 to different values on the right, then the relation would no longer be a function because 10.3, a single input, would have multiple outputs.
