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3 years ago

F(x)=8x^2-2x+3

Mathematics

2 answers:

alexdok [17]3 years ago

6 0

Answer:

-4x^2-6x+6

Step-by-step explanation:

We are asked to subtract g from f.

So the problem is:

[8x^2-2x+3]-[12x^2+4x-3]

So I'm going to distribute and write without [].

8x^2-2x+3-12x^2-4x+3

Now I'm going to pair up any like terms:

8x^2-12x^2-2x-4x+3+3

Simplifying:

-4x^2-6x+6

kirza4 [7]3 years ago

3 0

Answer: The correct option is

(C) $h(x)=-4x^2-6x+6.$

Step-by-step explanation: We are given the following two functions :

$f(x)=8x^2-2x+3,~~~~~g(x)=12x^2+4x-3.$

We are to find the value of h(x) if h(x) = f(x) - g(x).

To find the value of h(x), we must subtract the expression of g(x) from the expression of f(x).

The value of h(x) can be calculated as follows :

$h(x)\\\\=f(x)-g(x)\\\\=(8x^2-2x+3)-(12x^2+4x-3)\\\\=8x^2-2x+3-12x^2-4x+3\\\\=-4x^2-6x+6.$

Thus, the required value of h(x) is $-4x^2-6x+6.$

Option (C) is CORRECT.

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Which of the following statements are true?

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Answer:

B, C

Step-by-step explanation:

Consider all options:

A. The graph of the function $f(x)=\dfrac{1}{2}\sqrt[3]{x}$ is vertically shrunk by a factor $\frac{1}{2}$ the graph of the function $f(x)=\sqrt[3]{x},$ so the domain and the range of both functions are the same. This option is false.

B. The graph of the function $f(x)=\dfrac{1}{2}\sqrt[3]{x}$ is vertically shrunk by a factor $\frac{1}{2}$ the graph of the function $f(x)=\sqrt[3]{x},$ so the domain and the range of both functions are the same. This option is true.

C. The graph of the function $f(x)=\dfrac{1}{2}\sqrt[3]{(x-2)}$ is translated 2 units to the right and vertically shrunk by a factor $\frac{1}{2}$ the graph of the function $f(x)=\sqrt[3]{x},$ so their graphs are similar except the first graph is shifted right and shrunk vertically by a factor of $\frac{1}{2}.$ . This option is true.

D. The function $f(x)=\dfrac{1}{2}\sqrt{x}$ has the domain and the range all non-negative real values. The function $f(x)=\sqrt[3]{x}$ has the domain and the range all real values. So this option is false.