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riadik2000 [5.3K]
3 years ago
6

Solve each system by using substitution. 3x - y = 4 x + 5y = -4

Mathematics
1 answer:
babunello [35]3 years ago
5 0

Answer:

from \: last \: equation : \\ x =  - 4 - 5y -  -  - (a) \\ substitute \: in \: first \: equation \\ 3( - 4 - 5y) - y = 4 \\  - 12 - 15y - y = 4 \\  - 16y = 16 \\ y =  - 1 \\  \\ therefore \: from \: (a) \\ x =  - 4 - 5( - 1) \\ x = 1

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If f(x)=8x and g(x)=2x+1, what is (f×g)(x)
Sav [38]

Answer:

(f * g)(x) has a final product of 16x² + 8x.

Step-by-step explanation:

When you see (f * g)(x), this means that we are going to be multiply f(x) and g(x) together.

<em>f(x)=8x</em>

<em>g(x)=2x+1</em>

Now, we multiply these terms together.

(8x)(2x + 1)

Use the foil method to multiply.

16x² + 8x

So, the product of these terms is 16x² + 8x.

5 0
3 years ago
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kondor19780726 [428]

Answer:

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5 0
2 years ago
Consider the following quadratic function Part 3 of 6: Find the x-intercepts. Express it in ordered pairs.Part 4 of 6: Find the
maksim [4K]

Answer:

The line of symmetry is x = -3

Explanation:

Given a quadratic function, we know that the graph is a parabola. The general form of a parabola is:

y=ax^2+bx+c

The line of symmetry coincides with the x-axis of the vertex. To find the x-coordinate of the vertex, we can use the formula:

x_v=-\frac{b}{2a}

In this problem, we have:

y=-x^2-6x-13

Then:

a = -1

b = -6

We write now:

x_v=-\frac{-6}{2(-1)}=-\frac{-6}{-2}=-\frac{6}{2}=-3

Part 3:

For this part, we need to find the x-intercepts. This is, when y = 0:

-x^2-6x-13=0

To solve this, we can use the quadratic formula:

x_{1,2}=\frac{-(-6)\pm\sqrt{(-6)^2-4\cdot(-1)\cdot(-13)}}{2(-1)}

And solve:

x_{1,2}=\frac{6\pm\sqrt{36-52}}{-2}x_{1,2}=\frac{-6\pm\sqrt{-16}}{2}

Since there is no solution to the square root of a negative number, the function does not have any x-intercept. The correct option is ZERO x-intercepts.

Part 4:

To find the y intercept, we need to find the value of y when x = 0:

y=-0^2-6\cdot0-13=-13

The y-intercept is at (0, -13)

Part 5:

Now we need to find two points in the parabola. Let-s evaluate the function when x = 1 and x = -1:

x=1\Rightarrow y=-1^2-6\cdot1-13=-1-6-13=-20x=-1\Rightarrow y=-(-1)^2-6\cdot(-1)-13=-1+6-13=-8

The two points are:

(1, -20)

(-1, -8)

Part 6:

Now, we can use 3 points to find the graph of the parabola.

We can locate (1, -20) and (-1, -8)

The third could be the vertex. We need to find the y-coordinate of the vertex. We know that the x-coordinate of the vertex is x = -3

Then, y-coordinate of the vertex is:

y=-(-3)^2-6(-3)-13=-9+18-13=-4

The third point we can use is (-3, -4)

Now we can locate them in the cartesian plane:

And that's enough to get the full graph:

8 0
1 year ago
What is the solution (x, y) to the following system of equations below?
Arlecino [84]
The answer is x=3 and y=-8
5 0
3 years ago
Read 2 more answers
Find the nth term of this sequence, 3, 6, 9, 12
miss Akunina [59]

Answer:

\large\boxed{\sf n^{th} \ term =3n}}

Step-by-step explanation:

Find common difference from subtracting any term in the sequence with the previous term.

\large{\sf 6-3}=3

Apply nth term formula.

\large{\sf a_n=a_1+(n-1)d

\large{\sf d=3 \ \ a_1=3}

\large{\sf a_n=3+(n-1)3

\large{\sf a_n=3+3n-3

\large{\sf a_n=3n}

3 0
3 years ago
Read 2 more answers
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