The correct answer is B(OH)3 <AI(OH)3 < In(OH)3.
The metallic character of the group 1 elements first increases from Boron to Aluminium, then decreases from Aluminium to Thallium because of high ionization Enthalpy. Also, the larger size of the ion, the lesser is the ionization of Enthalpy.
Basic nature of the hydroxides of group 13 increases on moving down the group as the electro-positive character of elements increases.
Therefore, the correct order of increasing aqueous basicity is as follows:
B(OH)3 <AI(OH)3 < In(OH)3
What is the basic nature of group 13?
The metallic charecter of the elements affects their fundamental characteristics. The basicity rises as the metallic character does, and vice versa. Therefore, as we move lower in any given group, the atomic radius of the elements increases. Higher radii indicate that it would become increasingly challenging for the nucleus to rule over the electrons in the valency shell. Consequently, there will be a greater inclination for electron release. As a result, the metallic properties will improve, increasing the basicity of the oxides. Therefore, it follows that the basicity of the oxides would rise as we go down in a group.
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Answer:
The precautionary principle would prevent the implementation of technologies that possess a risk to humans, animals, and the environment. The strengths are that it will definately save the population and planet from a new technology that could cause long-term harm.
The weakness is that this principle may inhibit new technologies that are needed to help under-developed countries from preventing diseases. The precautionary principle states that technologies should entirely risk-free.
Explanation:
Elements are arranged by their atomic number, which is also the number of protons they have.
7000m is the answer as 1 km is 1000m ...so 7km multiplied by 1000m u get 7000 m...and always remember if u r converting a bigger unit to a smaller unit u multiply and if u r converting a smaller unit to a bigger unit u divide
Answer:
Q_d=35881 J/mol
So the activation energy is 35881 J/mol.
Explanation:
Consider the following equations:
Solving the above two equation to find the Q_d in term of diffusivity and temperature we will get:
where:
Q_d is the activation energy
D_1 is the diffusivity at T_1
D_2 is the diffusivity at T_2
Q_d=35881 J/mol
So the activation energy is 35881 J/mol.
= 899.88 moles