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blondinia [14]
2 years ago
10

Rank the following hydroxides in order of increasing aqueous basicity: Al(OH)₃, (OH)₃, In(OH)₃

Chemistry
1 answer:
vovangra [49]2 years ago
7 0

The correct answer is B(OH)3 <AI(OH)3 < In(OH)3.

The metallic character of the group 1 elements first increases from Boron to Aluminium, then decreases from Aluminium to Thallium because of high ionization Enthalpy. Also, the larger size of the ion, the lesser is the ionization of Enthalpy.

Basic nature of the hydroxides of group 13 increases on moving down the group as the electro-positive character of elements increases.

Therefore, the correct order of increasing aqueous basicity is as follows:

B(OH)3 <AI(OH)3 < In(OH)3

What is the basic nature of group 13?

The metallic charecter of the elements affects their fundamental characteristics. The basicity rises as the metallic character does, and vice versa. Therefore, as we move lower in any given group, the atomic radius of the elements increases. Higher radii indicate that it would become increasingly challenging for the nucleus to rule over the electrons in the valency shell. Consequently, there will be a greater inclination for electron release. As a result, the metallic properties will improve, increasing the basicity of the oxides. Therefore, it follows that the basicity of the oxides would rise as we go down in a group.

To learn more about hydroxides refer the link:

brainly.com/question/10134219

#SPJ4

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the beaker contains 0.2556 m h2so3 and the buret contains 0.3106 m naoh what happens to the conductivity during titration
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Before the equivalence point, conductivity is decreasing. After the equivalence point, conductivity is increasing

Explanation:

In solution H2SO3 produce H+ ions and SO3²⁻ ions. In the same way, NaOH produce Na⁺ and OH⁻ ions. The conductivity of a solution is directly proportional to the concentration of ions in a solution. During titration, you are adding more NaOH (That is, more Na⁺ and OH⁻ ions). But each moles of OH⁻ reacts with H⁺ ion producing H₂O. That means the moles of Na⁺ that you are adding = Moles of H⁺ are been consumed. The concentration of ions remains approximately constant. But, H⁺ ion conducts better than Na⁺ ion. That means before the equivalence point, conductivity is decreasing. But after the equivalence point you will add OH- ions in excess increasing ion concentration increasing the conductivity:

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